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Show that the Logarithmic Function F : R0+ → R Given by F (X) Loga X ,A> 0 Is A Bijection.

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Question

Show that the logarithmic function  f : R0+ → R   given  by f (x)  loga x ,a> 0   is   a  bijection.

Sum
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Solution

`f R^+ → R  given  by  f (x) = log_a  x , a > 0`

Injectivity:
Let x and y be any two elements in the domain (N), such that f(x) = f(y).

 f(x) = f(y)

`log_a  x + log _a y`

⇒ x = y

So, f is one-one.
Surjectivity:
Let y be any element in the co-domain (R), such that f(x) = y for some element x in R+(domain).

f(x) = y

 `log_a x = y`

⇒ `x = a^y in R^+`

So, for every element in the co-domain, there exists some pre-image in the domain.
⇒ f is onto.
Since f is one-one and onto, it is a bijection.

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Chapter 2: Functions - Exercise 2.1 [Page 32]

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R.D. Sharma Mathematics Volume 1 and 2 [English] Class 12
Chapter 2 Functions
Exercise 2.1 | Q 13 | Page 32

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