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If `F (X) = Sqrt(1-x)` And G(X) = Loge X Are Two Real Functions, Then Describe Functions Fog And Gof.

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Question

   if `f (x) = sqrt(1-x)` and g(x) = `log_e` x are two real functions, then describe functions fog and gof.

Sum
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Solution

`f (x) = sqrt(1-x)` 

For domain, 1-x≥0

⇒ x≤1

⇒ domain of f = (−∞, 1]

⇒ f : (−∞, 1] → (0,∞) 

g(x) = loge x

Clearly, g : (0, ∞) → R

Computation of fog :

Clearly, the range of g is not a subset of the domain of f.

So,we need to compute the domain of fog.

⇒ Domain (fog) = {x : x ∈ Domain (g) and g(x) ∈ Domain of f}

⇒ Domain (fog) = {x: x ∈ (0, ∞) and loge x ∈ (−∞, 1]}

⇒ Domain (fog) = { x: x ∈ (0, ∞) and x ∈ (0, e] }

⇒ Domain (fog)= {x : x ∈ (0, e]}

⇒ Domain (fog )= (0, e]

⇒ fog : (0, e) → R

So, (fog) (x) = f (g (x))

= f (loge x)

= `sqrt( 1-log_e  x)`

Computation of gof:Clearly, the range of f is  a subset of the domain of g.

⇒ gof : (−∞,1] → R

⇒ (gof) (x) = g (f (x))

= `g  (sqrt(1-x))`

= `log_e sqrt (1 - x)`

= `log_e (1 - x)^(1/2)`

= `1/2  log_e (1-x)`

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Chapter 2: Functions - Exercise 2.3 [Page 54]

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R.D. Sharma Mathematics Volume 1 and 2 [English] Class 12
Chapter 2 Functions
Exercise 2.3 | Q 8 | Page 54

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