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Which of the Following Functions from a = { X ∈ R : − 1 ≤ X ≤ 1 } (A) F ( X ) = | X | (B) F ( X ) = Sin π X 2 (C) F ( X ) = Sin π X 4 (D) None of These

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Question

Which of the following functions from

\[A = \left\{ x \in R : - 1 \leq x \leq 1 \right\}\]

 

Options

  • \[f\left( x \right) = |x|\]

  • \[f\left( x \right) = \sin\frac{\pi x}{2}\]

  • \[f\left( x \right) = \sin\frac{\pi x}{4}\]

  • None of these

MCQ
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Solution

\[f\left( x \right) = \sin\frac{\pi x}{2}\]

It is clear that  f(x) is one-one.

\[\text{Range of f} = \left[ \sin\frac{\pi\left( - 1 \right)}{2}, \sin\frac{\pi\left( 1 \right)}{2} \right] = \left[ \sin \frac{- \pi}{2}, \sin\frac{\pi}{2} \right] = \left[ - 1, 1 \right] = A = \text{Co domain of f}\]

⇒ f is onto.
So, f is a bijection.

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Chapter 2: Functions - Exercise 2.6 [Page 77]

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R.D. Sharma Mathematics Volume 1 and 2 [English] Class 12
Chapter 2 Functions
Exercise 2.6 | Q 27 | Page 77

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