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If the Rate of Change of Area of a Circle is Equal to the Rate of Change of Its Diameter, Then Its Radius is Equal to (A) 2 π Unit (B) 1 π Unit

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Question

If the rate of change of area of a circle is equal to the rate of change of its diameter, then its radius is equal to

Options

  • \[\frac{2}{\pi} \text { unit }\]

  •  \[\frac{1}{\pi} \text { unit }\]

  • \[\frac{\pi}{2} \text { units }\]

  • π units

MCQ
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Solution

 \[\frac{1}{\pi} \text { unit }\]

\[\text { Let r be the radius andAbe the area of the circle at any time t. Then,}\]

\[A=\pi r^2 \]

\[ \Rightarrow A = \frac{\pi D^2}{4} \left[ \because r = \frac{D}{2} \right]\]

\[ \Rightarrow \frac{dA}{dt} = \frac{\pi D}{2}\frac{dD}{dt}\]

\[ \Rightarrow \frac{dD}{dt} = \frac{\pi D}{2}\frac{dD}{dt} \left[ \because \frac{dA}{dt} = \frac{dD}{dt} \right]\]

\[ \Rightarrow \frac{D}{2} = \frac{1}{\pi}\]

\[ \Rightarrow r = \frac{1}{\pi} \text { units }\]

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Chapter 12: Derivative as a Rate Measurer - Exercise 13.4 [Page 25]

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RD Sharma Mathematics Volume 1 and 2 [English] Class 12
Chapter 12 Derivative as a Rate Measurer
Exercise 13.4 | Q 16 | Page 25

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