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Each Side of an Equilateral Triangle is Increasing at the Rate of 8 Cm/Hr. the Rate of Increase of Its Area When Side is 2 Cm, is (A) 8 √ 3 C M 2 / H R

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Question

Each side of an equilateral triangle is increasing at the rate of 8 cm/hr. The rate of increase of its area when side is 2 cm, is

Options

  • \[8\sqrt{3} \ {cm}^2 /hr\]

  • \[4\sqrt{3} \ {cm}^2 /hr\]

  • \[\frac{\sqrt{3}}{8} \ {cm}^2 /hr\]

  • none of these

MCQ
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Solution

 \[8\sqrt{3} \ {cm}^2 /hr\]

\[\text { Let x be the side and A be the area of the equilateral triangle at any time t. Then },\]

\[A = \frac{\sqrt{3}}{4} x^2 \]

\[ \Rightarrow \frac{dA}{dt} = \frac{\sqrt{3}}{2}x\left( \frac{dx}{dt} \right)\]

\[ \Rightarrow \frac{dA}{dt} = \frac{\sqrt{3}}{2}\left( 2 \right)\left( 8 \right)\]

\[ \Rightarrow \frac{dA}{dt} = 8\sqrt{3} \ {cm}^2 /hr\]

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Chapter 12: Derivative as a Rate Measurer - Exercise 13.4 [Page 25]

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R.D. Sharma Mathematics Volume 1 and 2 [English] Class 12
Chapter 12 Derivative as a Rate Measurer
Exercise 13.4 | Q 17 | Page 25

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