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The Radius of a Circle is Increasing at the Rate of 0.7 Cm/Sec. What is the Rate of Increase of Its Circumference?

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Question

The radius of a circle is increasing at the rate of 0.7 cm/sec. What is the rate of increase of its circumference?

Sum
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Solution

\[\text { Let r be the radius and C be the circumference of the circle at any time  t.Then },\]
\[C = 2\pi r\]
\[ \Rightarrow \frac{dC}{dt} = 2\pi\frac{dr}{dt}\]
\[ \Rightarrow \frac{dC}{dt} = 2\pi \times 0 . 7 \left[ \because\frac{dr}{dt}=0.7 cm/sec \right]\]
\[ \Rightarrow \frac{dC}{dt} = 1 . 4\pi cm/\sec\]

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Chapter 12: Derivative as a Rate Measurer - Exercise 13.2 [Page 19]

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R.D. Sharma Mathematics Volume 1 and 2 [English] Class 12
Chapter 12 Derivative as a Rate Measurer
Exercise 13.2 | Q 4 | Page 19

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