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The Radius of a Circle is Increasing at the Rate of 0.5 Cm/Sec. Find the Rate of Increase of Its Circumference ?

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Question

The radius of a circle is increasing at the rate of 0.5 cm/sec. Find the rate of increase of its circumference ?

Sum
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Solution

\[\text { Let r be the radius and C be the circumference of the circle at any time t.Then,}\]

\[C = 2\pi r\]

\[ \Rightarrow \frac{dC}{dt} = 2\pi\frac{dr}{dt}\]

\[ \Rightarrow \frac{dC}{dt} = 2\pi \times 0 . 5 \left[ \because\frac{dr}{dt}=0.5 cm/sec \right]\]

\[ \Rightarrow \frac{dC}{dt} = \pi cm/\sec\]

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Chapter 12: Derivative as a Rate Measurer - Exercise 13.3 [Page 24]

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R.D. Sharma Mathematics Volume 1 and 2 [English] Class 12
Chapter 12 Derivative as a Rate Measurer
Exercise 13.3 | Q 5 | Page 24

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