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Find the Rate of Change of the Total Surface Area of a Cylinder of Radius R and Height H, When the Radius Varies ?

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Question

Find the rate of change of the total surface area of a cylinder of radius r and height h, when the radius varies?

Sum
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Solution

Let T be the total surface area of a cylinder. Then,

T = \[2\pi r\left( r + h \right)\]

Since the radius varies, we differentiate the total surface area w.r.t. radius r .

Now,

\[\frac{dT}{dr} = \frac{d}{dr}\left[ 2\pi r\left( r + h \right) \right]\]

\[ \Rightarrow \frac{dT}{dr} = \frac{d}{dr}\left( 2\pi r^2 \right) + \frac{d}{dr}\left( 2\pi r h \right)\]

\[ \Rightarrow \frac{dT}{dr} = 4\pi r + 2\pi h\]

\[ \Rightarrow \frac{dT}{dr} = 2\pi\left(2r + h \right)\]

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Chapter 12: Derivative as a Rate Measurer - Exercise 13.1 [Page 4]

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R.D. Sharma Mathematics Volume 1 and 2 [English] Class 12
Chapter 12 Derivative as a Rate Measurer
Exercise 13.1 | Q 1 | Page 4

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