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Question
Find the rate of change of the total surface area of a cylinder of radius r and height h, when the radius varies?
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Solution
Let T be the total surface area of a cylinder. Then,
T = \[2\pi r\left( r + h \right)\]
Since the radius varies, we differentiate the total surface area w.r.t. radius r .
Now,
\[\frac{dT}{dr} = \frac{d}{dr}\left[ 2\pi r\left( r + h \right) \right]\]
\[ \Rightarrow \frac{dT}{dr} = \frac{d}{dr}\left( 2\pi r^2 \right) + \frac{d}{dr}\left( 2\pi r h \right)\]
\[ \Rightarrow \frac{dT}{dr} = 4\pi r + 2\pi h\]
\[ \Rightarrow \frac{dT}{dr} = 2\pi\left(2r + h \right)\]
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