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The Radius of a Sphere is Increasing at the Rate of 0.2 Cm/Sec. the Rate at Which the Volume of the Sphere Increase When Radius is 15 Cm, is (A) 12π Cm3/Sec (B) 180π Cm3/Sec

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Question

The radius of a sphere is increasing at the rate of 0.2 cm/sec. The rate at which the volume of the sphere increase when radius is 15 cm, is

Options

  • 12π cm3/sec

  • 180π cm3/sec

  • 225π cm3/sec

  • 3π cm3/sec

MCQ
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Solution

180π cm3/sec

\[\text { Let r be the radius andVbe the volume of the sphere at any timet.Then },\]

\[V=\frac{4}{3}\pi r^3 \]

\[\Rightarrow\frac{dV}{dt}=4\pi r^2 \frac{dr}{dt}\]

\[\Rightarrow\frac{dV}{dt}=4\pi \left( 15 \right)^2 \times 0 . 2\]

\[\Rightarrow\frac{dV}{dt} {=180\pi \ cm}^3 /sec\]

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Chapter 12: Derivative as a Rate Measurer - Exercise 13.4 [Page 25]

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R.D. Sharma Mathematics Volume 1 and 2 [English] Class 12
Chapter 12 Derivative as a Rate Measurer
Exercise 13.4 | Q 11 | Page 25

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