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The Radius of an Air Bubble is Increasing at the Rate of 0.5 Cm/Sec. at What Rate is the Volume of the Bubble Increasing When the Radius is 1 Cm? - Mathematics

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Question

The radius of an air bubble is increasing at the rate of 0.5 cm/sec. At what rate is the volume of the bubble increasing when the radius is 1 cm?

Sum
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Solution

\[\text { Let r be the radius and V be the volume of the air bubble at any time t. Then },\]
\[V=\frac{4}{3}\pi r^3 \]
\[\Rightarrow\frac{dV}{dt}=4\pi r^2 \frac{dr}{dt}\]
\[\Rightarrow\frac{dV}{dt}=4\pi \left( 1 \right)^2 \times 0.5\left( \because r = 1 \text{cm and } \frac{dr}{dt} = 0 . 5 cm/\sec \right)\]
\[\Rightarrow\frac{dV}{dt} {=2\pi cm}^3 /sec\]

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Chapter 13: Derivative as a Rate Measurer - Exercise 13.2 [Page 19]

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RD Sharma Mathematics [English] Class 12
Chapter 13 Derivative as a Rate Measurer
Exercise 13.2 | Q 7 | Page 19

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