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If a Particle Moves in a Straight Line Such that the Distance Travelled in Time T is Given by S = T3 − 6t2 + 9t + 8. Find the Initial Velocity of the Particle. - Mathematics

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Question

If a particle moves in a straight line such that the distance travelled in time t is given by s = t3 − 6t2+ 9t + 8. Find the initial velocity of the particle ?

Answer in Brief
Sum
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Solution

\[s = t^3 - 6 t^2 + 9t + 8\]

\[ \Rightarrow \frac{ds}{dt} = 3 t^2 - 12t + 9\]

\[\text { Initial velocity=Velocity at t }=0\]

\[ \Rightarrow \frac{ds}{dt} = 3 \left( 0 \right)^2 - 12\left( 0 \right) + 9\]

\[ \Rightarrow \frac{ds}{dt}=9 \text { units/unit time }\]

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Chapter 13: Derivative as a Rate Measurer - Exercise 13.3 [Page 24]

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RD Sharma Mathematics [English] Class 12
Chapter 13 Derivative as a Rate Measurer
Exercise 13.3 | Q 1 | Page 24

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