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In a Sphere the Rate of Change of Surface Area is (A) 8π Times the Rate of Change of Diameter (B) 2π Times the Rate of Change of Diameter (C) 2π Times the Rate of Change of Radius - Mathematics

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Question

In a sphere the rate of change of surface area is

Options

  • 8π times the rate of change of diameter

  • 2π times the rate of change of diameter

  • 2π times the rate of change of radius

  • 8π times the rate of change of radius

MCQ
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Solution

 8π times the rate of change of radius

\[\text { Let r be the radius and S be the surface area of the sphere at any time t .Then },\]

\[S = 4\pi r^2 \]

\[ \Rightarrow \frac{dS}{dt} = 8\pi r\frac{dr}{dt}\]

\[ \therefore \text { The rate of change of surface area is } 8\pi \text { times the rate of change of the radius.}\]

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Chapter 13: Derivative as a Rate Measurer - Exercise 13.4 [Page 26]

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RD Sharma Mathematics [English] Class 12
Chapter 13 Derivative as a Rate Measurer
Exercise 13.4 | Q 25 | Page 26

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