मराठी

In a Sphere the Rate of Change of Surface Area is (A) 8π Times the Rate of Change of Diameter (B) 2π Times the Rate of Change of Diameter (C) 2π Times the Rate of Change of Radius

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प्रश्न

In a sphere the rate of change of surface area is

पर्याय

  • 8π times the rate of change of diameter

  • 2π times the rate of change of diameter

  • 2π times the rate of change of radius

  • 8π times the rate of change of radius

MCQ
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उत्तर

 8π times the rate of change of radius

\[\text { Let r be the radius and S be the surface area of the sphere at any time t .Then },\]

\[S = 4\pi r^2 \]

\[ \Rightarrow \frac{dS}{dt} = 8\pi r\frac{dr}{dt}\]

\[ \therefore \text { The rate of change of surface area is } 8\pi \text { times the rate of change of the radius.}\]

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पाठ 12: Derivative as a Rate Measurer - Exercise 13.4 [पृष्ठ २६]

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आर.डी. शर्मा Mathematics Volume 1 and 2 [English] Class 12
पाठ 12 Derivative as a Rate Measurer
Exercise 13.4 | Q 25 | पृष्ठ २६

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