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Find an Angle θ Whose Rate of Increase Twice is Twice the Rate of Decrease of Its Cosine ? - Mathematics

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प्रश्न

Find an angle θ whose rate of increase twice is twice the rate of decrease of its cosine ?

बेरीज
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उत्तर

\[\text { Let x } = \cos\theta\]

\[\text { Differentiating both sides with respect to t, we get }\]

\[\frac{d x}{d t} = \frac{d \left( \cos\theta \right)}{d t}\]

\[ = - \sin\theta\frac{d \theta}{d t}\]

\[\text { But it is given that } \frac{d \theta}{d t} = - 2\frac{d x}{d t}\]

\[ \Rightarrow \frac{d x}{d t} = - \sin\theta\left( - 2\frac{d x}{d t} \right)\]

\[ \Rightarrow \sin\theta = \frac{1}{2}\]

\[ \Rightarrow \theta = \frac{\pi}{6}\]

\[\text { Hence }, \theta = \frac{\pi}{6} .\]

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पाठ 13: Derivative as a Rate Measurer - Exercise 13.2 [पृष्ठ २०]

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आरडी शर्मा Mathematics [English] Class 12
पाठ 13 Derivative as a Rate Measurer
Exercise 13.2 | Q 16.2 | पृष्ठ २०

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