मराठी

Find an Angle θ Which Increases Twice as Fast as Its Cosine ?

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प्रश्न

Find an angle θ which increases twice as fast as its cosine ?

बेरीज
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उत्तर

\[\text { Let x  }= \cos\theta\]
\[\text { Differentiating both sides with respect to t, we get }\]
\[\frac{d x}{d t} = \frac{d \left( \cos\theta \right)}{d t}\]
\[ = - \sin\theta\frac{d \theta}{d t}\]
\[\text { But it is given that } \frac{d \theta}{d t} = 2\frac{d x}{d t}\]
\[ \Rightarrow \frac{d x}{d t} = - \sin\theta\left( 2\frac{d x}{d t} \right)\]
\[ \Rightarrow \sin\theta = - \frac{1}{2}\]
\[ \Rightarrow \theta = \pi + \frac{\pi}{6} = \frac{7\pi}{6}\]
\[\text { Hence,} \theta = \frac{7\pi}{6} .\]

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पाठ 12: Derivative as a Rate Measurer - Exercise 13.2 [पृष्ठ २०]

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आर.डी. शर्मा Mathematics Volume 1 and 2 [English] Class 12
पाठ 12 Derivative as a Rate Measurer
Exercise 13.2 | Q 16.1 | पृष्ठ २०

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