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If a Particle Moves in a Straight Line Such that the Distance Travelled in Time T is Given by S = T3 − 6t2 + 9t + 8. Find the Initial Velocity of the Particle.

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प्रश्न

If a particle moves in a straight line such that the distance travelled in time t is given by s = t3 − 6t2+ 9t + 8. Find the initial velocity of the particle ?

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उत्तर

\[s = t^3 - 6 t^2 + 9t + 8\]

\[ \Rightarrow \frac{ds}{dt} = 3 t^2 - 12t + 9\]

\[\text { Initial velocity=Velocity at t }=0\]

\[ \Rightarrow \frac{ds}{dt} = 3 \left( 0 \right)^2 - 12\left( 0 \right) + 9\]

\[ \Rightarrow \frac{ds}{dt}=9 \text { units/unit time }\]

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अध्याय 12: Derivative as a Rate Measurer - Exercise 13.3 [पृष्ठ २४]

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आर.डी. शर्मा Mathematics Volume 1 and 2 [English] Class 12
अध्याय 12 Derivative as a Rate Measurer
Exercise 13.3 | Q 1 | पृष्ठ २४

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