Advertisements
Advertisements
Question
Given alongside is the velocity-time graph for a moving body :
Find :
(i) Velocity of the body at point C.
(ii) Acceleration acting on the body between A and B.
(iii) Acceleration acting on the body between B and C.
Advertisements
Solution
(i) BC represents uniform velocity. So velocity of the body at point C is 40 km
(ii) Acceleration = Slope of line AB
= `((40-20))/((3-0)) (km)/(hr^2)`
= 6.66 `"km/hr"^2`
(iii) BC represents uniform velocity, so, acceleration acting on the body is zero.
APPEARS IN
RELATED QUESTIONS
Show by using the graphical method that: `s=ut+1/2at^2` where the symbols have their usual meanings.
Multiple choice Question. Select the correct option.
In the velocity-time graph, the acceleration is
Draw velocity – time graph for the following situation:
When a body, is moving with uniform velocity.
The area of the right triangle under a speed-time graph is 500 m, in a time interval of 20 s. What is the speed of the body? Is the motion uniform or non-uniform?
Draw the speed-time graph of a body when its initial speed is not zero and the speed increases uniformly with time.
What can you conclude if the speed-time graph of a body is a curve moving upwards starting from the origin?
Draw distance-time graph to show:
Increasing velocity
Draw velocity-time graph to show:
Deceleration
Write a sentence to explain the shape of graph.
Saphira moves at a constant speed in the same direction. Rephrase the same sentence in fewer words using concepts related to motion.
An object is moving in a positive direction with positive acceleration. The velocity-time graph with constant acceleration which represents the above situation is:
