Advertisements
Advertisements
प्रश्न
Given alongside is the velocity-time graph for a moving body :
Find :
(i) Velocity of the body at point C.
(ii) Acceleration acting on the body between A and B.
(iii) Acceleration acting on the body between B and C.
Advertisements
उत्तर
(i) BC represents uniform velocity. So velocity of the body at point C is 40 km
(ii) Acceleration = Slope of line AB
= `((40-20))/((3-0)) (km)/(hr^2)`
= 6.66 `"km/hr"^2`
(iii) BC represents uniform velocity, so, acceleration acting on the body is zero.
APPEARS IN
संबंधित प्रश्न
A body is moving uniformly in a straight line with a velocity of 5 m/s. Find graphically the distance covered by it in 5 seconds.
What does the slope of velocity-time graph represent?
Interpret the following graph:
Draw velocity-time graph to show:
Zero acceleration
Write a sentence to explain the shape of graph.
Saphira moves at a constant speed in the same direction. Rephrase the same sentence in fewer words using concepts related to motion.
Which of the following can determine the acceleration of a moving object.
From the v-t graph, ______ can be calculated.
Slope of the velocity-time graph gives ______.
An object is moving in a positive direction with positive acceleration. The velocity-time graph with constant acceleration which represents the above situation is:
If the velocity-time graph has the shape AMB, what would be the shape of the corresponding acceleration-time graph?
