Advertisements
Advertisements
प्रश्न
A body is moving uniformly in a straight line with a velocity of 5 m/s. Find graphically the distance covered by it in 5 seconds.
Advertisements
उत्तर
We have to calculate the distance travelled by the moving body whose speed time graph is given to us.
Distance travelled = Area of rectangle OABC
So, distance travelled,
= (OA)(OC)
= (5)(5) m
= 25 m
APPEARS IN
संबंधित प्रश्न
What is the quantity which is measured by the area occupied below the velocity-time graph?
Study the speed-time graph of a car given alongside and answer the following questions:
(i) What type of motion is represented by OA ?
(ii) What type of motion is represented by AB ?
(iii) What type of motion is represented by BC ?
(iv) What is the acceleration of car from O to A ?
(v)What is the acceleration of car from A to B ?
(vi) What is the retardation of car from B to C ?
What does the slope of velocity-time graph represent?
From the displacement-time graph of a cyclist given below in the Figure, find The time after which he reaches the starting point .
Diagram shows a velocity – time graph for a car starting from rest. The graph has three sections AB, BC, and CD.
In which section, car has a zero acceleration?
Represent the position of a body described as at 15 m, 30o north of west, on a graph paper.
How will you use a speed-time graph to find whether the acceleration of the body is uniform or not?
What can you say about the motion of a body if:
Its time-velocity graph is a straight line
Draw the distance-time graphs of the bodies P and Q starting from rest, moving with uniform speeds with P moving faster than Q.
Figure shows the distance-time graph of three students A, B and C. On the basis of the graph, answer the following :
When B meets A, where is C?
