Advertisements
Advertisements
प्रश्न
The speed-time graph of an ascending passenger lift is given alongside. What is the acceleration of the lift:
(1) during the first two seconds ?
(2) between second and tenth second ?
(3) during the last two seconds ?
Advertisements
उत्तर
(i) We have to find the acceleration from the given graph.
Acceleration = slope of line AB
= `((4.6-0))/((2-0)) "m/s"^2`
= 2.3 `"m/s"^2`
(ii) Between second and tenth second, it represents uniform speed, so, acceleration acting on the lift is zero.
(iii) During the last two seconds, it represents retardation of the lift, so its acceleration is (–2.3 m/s2).
APPEARS IN
संबंधित प्रश्न
Name the two quantities, the slope of whose graph give acceleration.
Show by means of graphical method that: v = u + at, where the symbols have their usual meanings.
Three speed-time graphs are given below :
Which graph represents the case of:
(i) a cricket ball thrown vertically upwards and returning to the hands of the thrower ?
(ii) a trolley decelerating to a constant speed and then accelerating uniformly ?
Define speed. What is its S.I. unit?
Draw displacement – time graph for the following situation:
When a body is stationary.
A train starting from rest picks up a speed of 20 ms−1 in 200 s. It continues to move at the same rate for the next 500 s and is then brought to rest in another 100 s.
- Plot a speed-time graph.
- From graph calculate
(a) uniform rate of acceleration
(b) uniform rate of retardation
(c) total distance covered before stopping
(d) average speed.
Draw distance-time graph to show:
Decreasing velocity
Draw velocity-time graph to show:
Zero acceleration
Write a sentence to explain the shape of graph.
The given graph shows the variation of velocity (v) with position (x) for a particle moving along a straight line
Which of the following graph shows the variation of acceleration (a) with position (x)?
If the velocity-time graph has the shape AMB, what would be the shape of the corresponding acceleration-time graph?
