Advertisements
Advertisements
प्रश्न
Multiple choice Question. Select the correct option.
The distance covered in the adjoining velocity-time graph is :
पर्याय
25 m
40 m
50 m
45 m
Advertisements
उत्तर
50 m
Explanation:
Distance covered = Area under velocity – time graph
=1/2 × base × height
a = 1/2 × 5 × 20 = 50 m
APPEARS IN
संबंधित प्रश्न
Draw a velocity-time graph to show the following motion :
A car accelerates uniformly from rest for 5 s ; then it travels at a steady’ velocity for 5 s.
What can you say about the motion of a body if:
its displacement-time graph is a straight line ?
What type of motion is represented by the following graph ?
What type of motion is represented by the following graph ?
Draw a displacement-time graph for a boy going to school with uniform velocity.
Diagram shows a velocity – time graph for a car starting from rest. The graph has three sections AB, BC and CD.
From a study of this graph, state how the distance travelled in any section is determined.
Diagram shows a velocity – time graph for a car starting from rest. The graph has three sections AB, BC, and CD.
In which section, car has a zero acceleration?
A ball is thrown up vertically and returns back to thrower in 6 s. Assuming there is no air friction, plot a graph between velocity and time. From the graph calculate
- deceleration
- acceleration
- total distance covered by ball
- average velocity.
A body at rest is thrown downward from the top of the tower. Draw a distance – time graph of its free fall under gravity during the first 3 seconds. Show your table of values starting t = 0 with an interval of 1 second, (g = 10 ms−2).
From the diagram given below, calculate distance covered by body.
