Advertisements
Advertisements
प्रश्न
From the diagram given below, calculate distance covered by body.
Advertisements
उत्तर
Distance covered = area under v.t. graph
= area of ΔOAC + area of ΔABC
= `1/2xx"OC"xx"AC"+1/2xx"BC"xx"AC"`
= `1/2xx10xx15+1/2xx6xx15`
= 5 × 15 + 3 × 15
= 75 + 45
= 120 m
APPEARS IN
संबंधित प्रश्न
What can you say about the motion of a body if its speed-time graph is a straight line parallel to the time axis ?
Fill in the following blank with suitable word :
In a speed-time graph, the area enclosed by the speed-time curve and the time axis gives the…………….. by the body.
Name the two quantities, the slope of whose graph give acceleration.
Show by using the graphical method that: `s=ut+1/2at^2` where the symbols have their usual meanings.
What can you say about the motion of a body if:
its velocity-time graph is a straight line ?
The speed-time graph of an ascending passenger lift is given alongside. What is the acceleration of the lift:
(1) during the first two seconds ?
(2) between second and tenth second ?
(3) during the last two seconds ?
Study the speed-time graph of a car given alongside and answer the following questions:
(i) What type of motion is represented by OA ?
(ii) What type of motion is represented by AB ?
(iii) What type of motion is represented by BC ?
(iv) What is the acceleration of car from O to A ?
(v)What is the acceleration of car from A to B ?
(vi) What is the retardation of car from B to C ?
What does the slope of a displacement-time graph represent?
Draw the following graph:
Speed versus time for a stepped motion
Figure shows displacement- time graph of two objects A and B moving in a stra ight line. Which object is moving fa ster?
