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प्रश्न
From the diagram given below, calculate distance covered by body.
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उत्तर
Distance covered = area under v.t. graph
= area of ΔOAC + area of ΔABC
= `1/2xx"OC"xx"AC"+1/2xx"BC"xx"AC"`
= `1/2xx10xx15+1/2xx6xx15`
= 5 × 15 + 3 × 15
= 75 + 45
= 120 m
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संबंधित प्रश्न
A body with an initial velocity x moves with a uniform acceleration y. Plot its velocity-time graph.
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(ii) What type of motion is represented by AB ?
(iii) What type of motion is represented by BC ?
(iv) What is the acceleration of car from O to A ?
(v)What is the acceleration of car from A to B ?
(vi) What is the retardation of car from B to C ?
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(c) total distance covered before stopping
(d) average speed.
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