Advertisements
Advertisements
प्रश्न
From the diagram given below, calculate deceleration.
Advertisements
उत्तर
Deceleration = Slope of v.t. graph from A to B
= `"AC"/"CB"=15/(16-10)=15/6` = 2.5 ms−2
APPEARS IN
संबंधित प्रश्न
An object of mass 16 kg is moving with an acceleration of 3 m/s2. Calculate the applied force. If the same force is applied to an object of mass 24 kg, how much will be the acceleration?
State the type of motion represented by the following sketches in Figures.
Give an example of each type of motion.
Figure given below shows a velocity-time graph for a car starting from rest. The graph has three parts AB, BC and CD.
(a) Is the magnitude of acceleration higher or lower than that of retardation ? Give a reason .
(b) Compare the magnitude of acceleration and retardation .
A car travels with uniform velocity of 25 m s-1 for 5 s. The brakes are then applied and the car is uniformly retarded and comes to rest in further 10 s. Find:
- The distance which the car travels before the brakes are applied,
- Retardation and
- The distance travelled by car after applying the brakes.
A vehicle is accelerating on a straight road. Its velocity at any instant is 30 km/h. After 2 s, it is 33.6 km/h, and after further 2 s, it is 37.2 km/h. Find the acceleration of the vehicle in m s-2. Is the acceleration uniform?
When is the acceleration due to gravity negative?
What is the SI unit of acceleration?
A body has an acceleration of -3.5 ms-2. What is its retardation?
Exercise Problem.
A racing car has a uniform acceleration of 4 ms–2. What distance it covers in 10 s after the start?
A boy throws a ball up and catches it when the ball falls back. In which part of the motion the ball is accelerating?
