Advertisements
Advertisements
प्रश्न
Diagram is given below shows velocity – time graph of car P and Q, starting from the same place and in the same direction. Calculate which car is ahead after 10 s and by how much?
Advertisements
उत्तर
Distance covered by car P = area of ΔOAB
= `1/2xx"OB"xx"AB"`
= `1/2xx10xx35`
= 175 m
Distance covered by car Q = area of ΔCDE + area of rectangle DFBE
= `1/2xx"CE"xx"DE"+"EB"xx"BF"`
= `1/2xx(5-2)xx25+(10-5)xx25`
= `75/2+125`
= 37.5 + 125
= 162.5 m
So, car P is a head of car Q by (175 − 162.5) m
i.e. by 12.5 m
APPEARS IN
संबंधित प्रश्न
What does the slope of a displacement-time graph represent?
For uniform motion _________
Draw velocity – time graph for the following situation:
When a body, is moving with uniform velocity.
A train starting from rest picks up a speed of 20 ms−1 in 200 s. It continues to move at the same rate for the next 500 s and is then brought to rest in another 100 s.
- Plot a speed-time graph.
- From graph calculate
(a) uniform rate of acceleration
(b) uniform rate of retardation
(c) total distance covered before stopping
(d) average speed.
A body at rest is thrown downward from the top of the tower. Draw a distance – time graph of its free fall under gravity during the first 3 seconds. Show your table of values starting t = 0 with an interval of 1 second, (g = 10 ms−2).
From the diagram given below, calculate distance covered by body.
Draw distance-time graph to show:
Decreasing velocity
What does the slope of velocity-time graph represent?
The slope of the speed–time graph gives ______.
From the v-t graph, ______ can be calculated.
