हिंदी

Draw the following graph:Speed versus time for a fluctuating speed.

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प्रश्न

Draw the following graph:
Speed versus time for a fluctuating speed.

आकृति
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उत्तर

Speed time graph for a body showing fluctuating speed.

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अध्याय 2: Motion in One Dimension - Exercise 2 [पृष्ठ ८०]

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फ्रैंक Physics Part 1 [English] Class 9 ICSE
अध्याय 2 Motion in One Dimension
Exercise 2 | Q 58.4 | पृष्ठ ८०

संबंधित प्रश्न

A body with an initial velocity x moves with a uniform acceleration y. Plot its velocity-time graph.


Draw velocity – time graph for the following situation:

When a body, is moving with uniform velocity.


A ball is thrown up vertically and returns back to thrower in 6 s. Assuming there is no air friction, plot a graph between velocity and time. From the graph calculate

  1. deceleration
  2. acceleration
  3. total distance covered by ball
  4. average velocity.

Diagram is given below shows velocity – time graph of car P and Q, starting from the same place and in the same direction. Calculate at what time intervals both cars have the same velocity?


Draw the speed-time graph of a body when its initial speed is not zero and the speed increases uniformly with time.


What can you conclude if the speed-time graph of a body is a straight line sloping upwards and not passing through the origin?


Interpret the following graph:


What can you say about the motion of a body if:
Its time-velocity graph is a straight line


(i) In speed time graph uniform motion is given by a straight line parallel to x axis so figure (a) denotes the uniform motion.
(ii) In speed time graph motion with increasing speed is shown by straight line with positive slope so figure (c) denotes the motion with speed increasing.
(iii) In speed time graph motion with decreasing speed is shown by straight line with negative slope so figure (b) denotes the motion with speed decreasing.
(iv) In speed time graph motion with oscillating speed is shown by zigzag line so figure {d) denotes the motion with speed oscillating.


From the v-t graph, ______ can be calculated.


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