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प्रश्न
A body is moving uniformly in a straight line with a velocity of 5 m/s. Find graphically the distance covered by it in 5 seconds.
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उत्तर
We have to calculate the distance travelled by the moving body whose speed time graph is given to us.
Distance travelled = Area of rectangle OABC
So, distance travelled,
= (OA)(OC)
= (5)(5) m
= 25 m
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संबंधित प्रश्न
Fill in the following blank with suitable word :
In a speed-time graph, the area enclosed by the speed-time curve and the time axis gives the…………….. by the body.
What type of motion is represented by the following graph ?

Multiple choice Question. Select the correct option.
The distance covered in the adjoining velocity-time graph is :

Diagram shows a velocity – time graph for a car starting from rest. The graph has three sections AB, BC, and CD.

In which section, car has a zero acceleration?
From the velocity – time graph given below, calculate Average velocity in region CED.

Name the physical quantity which is equal to the area under speed-time graph.
Draw the following graph:
Speed versus time for a stepped motion
Draw velocity-time graph to show:
Deceleration
Write a sentence to explain the shape of graph.
Draw velocity-time graph to show:
Zero acceleration
Write a sentence to explain the shape of graph.
Slope of the velocity-time graph gives ______.
