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प्रश्न
The speed-time graph of an ascending passenger lift is given alongside. What is the acceleration of the lift:
(1) during the first two seconds ?
(2) between second and tenth second ?
(3) during the last two seconds ?
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उत्तर
(i) We have to find the acceleration from the given graph.
Acceleration = slope of line AB
= `((4.6-0))/((2-0)) "m/s"^2`
= 2.3 `"m/s"^2`
(ii) Between second and tenth second, it represents uniform speed, so, acceleration acting on the lift is zero.
(iii) During the last two seconds, it represents retardation of the lift, so its acceleration is (–2.3 m/s2).
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संबंधित प्रश्न
What can you say about the motion of a body if:
its displacement-time graph is a straight line ?
What can you say about the motion of a body if:
its velocity-time graph is a straight line ?
Draw the speed-time graph of a body starting from some point P, gradually picking up speed, then running at a uniform speed and finally slowing down to stop at some point Q.
What can you conclude if the speed-time graph of a body is a curve moving upwards starting from the origin?
What can you conclude if the speed-time graph of a body is a straight line sloping upwards and not passing through the origin?
Draw the following graph:
Speed versus time for a non-uniform acceleration.
Interpret the following graph:
Figure shows displacement- time graph of two objects A and B moving in a stra ight line. Which object is moving fa ster?
What can you say about the motion of a body if:
Its time-velocity graph is a straight line
Derive the equation
S = ut+ `1/2` at2
Using a speed- time graph
