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प्रश्न
Given alongside is the velocity-time graph for a moving body :
Find :
(i) Velocity of the body at point C.
(ii) Acceleration acting on the body between A and B.
(iii) Acceleration acting on the body between B and C.
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उत्तर
(i) BC represents uniform velocity. So velocity of the body at point C is 40 km
(ii) Acceleration = Slope of line AB
= `((40-20))/((3-0)) (km)/(hr^2)`
= 6.66 `"km/hr"^2`
(iii) BC represents uniform velocity, so, acceleration acting on the body is zero.
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