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Question
Diagram is given below shows velocity – time graph of car P and Q, starting from the same place and in the same direction. Calculate which car is ahead after 10 s and by how much?
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Solution
Distance covered by car P = area of ΔOAB
= `1/2xx"OB"xx"AB"`
= `1/2xx10xx35`
= 175 m
Distance covered by car Q = area of ΔCDE + area of rectangle DFBE
= `1/2xx"CE"xx"DE"+"EB"xx"BF"`
= `1/2xx(5-2)xx25+(10-5)xx25`
= `75/2+125`
= 37.5 + 125
= 162.5 m
So, car P is a head of car Q by (175 − 162.5) m
i.e. by 12.5 m
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