Advertisements
Advertisements
Question
Multiple choice Question. Select the correct option.
The distance covered in the adjoining velocity-time graph is :
Options
25 m
40 m
50 m
45 m
Advertisements
Solution
50 m
Explanation:
Distance covered = Area under velocity – time graph
=1/2 × base × height
a = 1/2 × 5 × 20 = 50 m
APPEARS IN
RELATED QUESTIONS
Show by using the graphical method that: `s=ut+1/2at^2` where the symbols have their usual meanings.
Draw a displacement-time graph for a boy going to school with uniform velocity.
Draw velocity – time graph for the following situation:
When a body is moving with variable velocity, but uniform acceleration.
A train starting from rest picks up a speed of 20 ms−1 in 200 s. It continues to move at the same rate for the next 500 s and is then brought to rest in another 100 s.
- Plot a speed-time graph.
- From graph calculate
(a) uniform rate of acceleration
(b) uniform rate of retardation
(c) total distance covered before stopping
(d) average speed.
What can you conclude if the speed-time graph of a body is a curve moving upwards starting from the origin?
Draw distance-time graph to show:
Increasing velocity
Interpret the following graph:
Figure shows the distance-time graph of three students A, B and C. On the basis of the graph, answer the following :
When B meets A, where is C?
State whether true or false. If false, correct the statement.
The velocity – time graph of a particle falling freely under gravity would be a straight line parallel to the x axis.
The area under the v-t graph represents a physical quantity that has the unit.
