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प्रश्न
A body at rest is thrown downward from the top of the tower. Draw a distance – time graph of its free fall under gravity during the first 3 seconds. Show your table of values starting t = 0 with an interval of 1 second, (g = 10 ms−2).
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उत्तर
Initial velocity = M = 0
Acceleration = a = +g = 10 ms−2
when t = Is, then distance travelled (S), is given by
S1 = ut + `1/2` at2
S1 = `0(1)+1/2(10)(1)^2`
S1 = 5m
When t = 2s then S2 = ut + `1/2` at2
S2 = `(0)(2)+1/2(10)(2)^2`
S2 = 5(4) = 20 m
When t = 3s, then S3 = ut + `1/2` at2
S3 = `(0)(3)+1/2(10)(3)^2`
S = 5 (9) = 45 m
| Time | 1s | 2s | 3s |
| Distance covered | 5 m | 20 m | 45 m |
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