Question

A body at rest is thrown downward from the top of the tower. Draw a distance – time graph of its free fall under gravity during the first 3 seconds. Show your table of values starting t = 0 with an interval of 1 second, (g = 10 ms⁻²).

Answer 1

Initial velocity = M = 0
Acceleration = a = +g = 10 ms⁻²
when t = Is, then distance travelled (S), is given by

S₁ = ut + `1/2` at²

S₁ = `0(1)+1/2(10)(1)^2`

S₁ = 5m

When t = 2s then S₂ = ut + `1/2` at²

S₂ = `(0)(2)+1/2(10)(2)^2`

S₂ = 5(4) = 20 m

When t = 3s, then S₃ = ut + `1/2` at²

S₃ = `(0)(3)+1/2(10)(3)^2`

S = 5 (9) = 45 m

Time	1s	2s	3s
Distance covered	5 m	20 m	45 m