Advertisements
Advertisements
प्रश्न
Draw distance-time graph to show:
Decreasing velocity
Advertisements
उत्तर
As slope of this line is negative so this represent decreasing velocity.
APPEARS IN
संबंधित प्रश्न
Derive the following equation of motion by the graphical method : v2 = u2 + 2as, where the symbols have their usual meanings.
Diagram shows a velocity – time graph for a car starting from rest. The graph has three sections AB, BC, and CD.
In which section, car has a zero acceleration?
A train starting from rest picks up a speed of 20 ms−1 in 200 s. It continues to move at the same rate for the next 500 s and is then brought to rest in another 100 s.
- Plot a speed-time graph.
- From graph calculate
(a) uniform rate of acceleration
(b) uniform rate of retardation
(c) total distance covered before stopping
(d) average speed.
What can you conclude if the speed-time graph of a body is a curve moving upwards starting from the origin?
Draw distance-time graph to show:
Uniform velocity
Derive the equation
S = ut+ `1/2` at2
Using a speed- time graph
(i) In speed time graph uniform motion is given by a straight line parallel to x axis so figure (a) denotes the uniform motion.
(ii) In speed time graph motion with increasing speed is shown by straight line with positive slope so figure (c) denotes the motion with speed increasing.
(iii) In speed time graph motion with decreasing speed is shown by straight line with negative slope so figure (b) denotes the motion with speed decreasing.
(iv) In speed time graph motion with oscillating speed is shown by zigzag line so figure {d) denotes the motion with speed oscillating.
The area under the v-t graph represents a physical quantity that has the unit.
Which of the following can determine the acceleration of a moving object.
An object is moving in a positive direction with positive acceleration. The velocity-time graph with constant acceleration which represents the above situation is:
