English

Find the Sum of the Following Geometric Series: X3, X5, X7, ... to N Terms

Advertisements
Advertisements

Question

Find the sum of the following geometric series:

x3, x5, x7, ... to n terms

Sum
Advertisements

Solution

The given G.P. is  x3, x5, x7 ........

Here, a = x3 and r = x

`"S"_"n" = (a(1 - r^n))/(1 - r)`

= `(x^3[1 - (x^2)^n])/(1 - x^2)`

= `(x^3(1 - x^(2n)))/(1 - x^2)`

shaalaa.com
  Is there an error in this question or solution?
Chapter 20: Geometric Progression - Exercise 20.3 [Page 27]

APPEARS IN

R.D. Sharma Mathematics [English] Class 11
Chapter 20 Geometric Progression
Exercise 20.3 | Q 2.8 | Page 27

Video TutorialsVIEW ALL [1]

RELATED QUESTIONS

Find the 12th term of a G.P. whose 8th term is 192 and the common ratio is 2.


The 5th, 8th and 11th terms of a G.P. are p, q and s, respectively. Show that q2 = ps.


For what values of x, the numbers  `-2/7, x, -7/2` are in G.P?


Find the sum to 20 terms in the geometric progression 0.15, 0.015, 0.0015,…


Given a G.P. with a = 729 and 7th term 64, determine S7.


The sum of some terms of G.P. is 315 whose first term and the common ratio are 5 and 2, respectively. Find the last term and the number of terms.


The first term of a G.P. is 1. The sum of the third term and fifth term is 90. Find the common ratio of G.P.


Show that the sequence <an>, defined by an = \[\frac{2}{3^n}\], n ϵ N is a G.P.


Find:
the ninth term of the G.P. 1, 4, 16, 64, ...


Find :

the 10th term of the G.P.

\[\sqrt{2}, \frac{1}{\sqrt{2}}, \frac{1}{2\sqrt{2}}, . . .\]


Which term of the G.P. :

\[\sqrt{2}, \frac{1}{\sqrt{2}}, \frac{1}{2\sqrt{2}}, \frac{1}{4\sqrt{2}}, . . . \text { is }\frac{1}{512\sqrt{2}}?\]


The fourth term of a G.P. is 27 and the 7th term is 729, find the G.P.


If the G.P.'s 5, 10, 20, ... and 1280, 640, 320, ... have their nth terms equal, find the value of n.


The 4th term of a G.P. is square of its second term, and the first term is − 3. Find its 7th term.


Find the sum of the following geometric series:

`3/5 + 4/5^2 + 3/5^3 + 4/5^4 + ....` to 2n terms;


Find the sum of the following geometric series:

1, −a, a2, −a3, ....to n terms (a ≠ 1)


How many terms of the G.P. 3, 3/2, 3/4, ... be taken together to make \[\frac{3069}{512}\] ?


Find the sum :

\[\sum^{10}_{n = 1} \left[ \left( \frac{1}{2} \right)^{n - 1} + \left( \frac{1}{5} \right)^{n + 1} \right] .\]


Find the sum of the following series to infinity:

`1/3+1/5^2 +1/3^3+1/5^4 + 1/3^5 + 1/56+ ...infty`


One side of an equilateral triangle is 18 cm. The mid-points of its sides are joined to form another triangle whose mid-points, in turn, are joined to form still another triangle. The process is continued indefinitely. Find the sum of the (i) perimeters of all the triangles. (ii) areas of all triangles.


Show that in an infinite G.P. with common ratio r (|r| < 1), each term bears a constant ratio to the sum of all terms that follow it.


The sum of three numbers which are consecutive terms of an A.P. is 21. If the second number is reduced by 1 and the third is increased by 1, we obtain three consecutive terms of a G.P. Find the numbers.


If a, b, c are in G.P., prove that:

a (b2 + c2) = c (a2 + b2)


If a, b, c, d are in G.P., prove that:

(a2 + b2 + c2), (ab + bc + cd), (b2 + c2 + d2) are in G.P.


If the 4th, 10th and 16th terms of a G.P. are x, y and z respectively. Prove that x, y, z are in G.P.


If (p + q)th and (p − q)th terms of a G.P. are m and n respectively, then write is pth term.


The value of 91/3 . 91/9 . 91/27 ... upto inf, is 


If the sum of first two terms of an infinite GP is 1 every term is twice the sum of all the successive terms, then its first term is 


The nth term of a G.P. is 128 and the sum of its n terms is 255. If its common ratio is 2, then its first term is ______.


For the G.P. if a = `7/243`, r = 3 find t6.


For what values of x, the terms `4/3`, x, `4/27` are in G.P.?


The numbers 3, x, and x + 6 form are in G.P. Find 20th term.


The numbers 3, x, and x + 6 form are in G.P. Find nth term


The numbers x − 6, 2x and x2 are in G.P. Find nth term


For the following G.P.s, find Sn

0.7, 0.07, 0.007, .....


For a G.P. If t3 = 20 , t6 = 160 , find S7


Determine whether the sum to infinity of the following G.P.s exist, if exists find them:

`1/2, 1/4, 1/8, 1/16,...`


Find : `sum_("n" = 1)^oo 0.4^"n"`


If the A.M. of two numbers exceeds their G.M. by 2 and their H.M. by `18/5`, find the numbers.


If in a geometric progression {an}, a1 = 3, an = 96 and Sn = 189, then the value of n is ______.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×