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Find the 12th term of a G.P. whose 8th term is 192 and the common ratio is 2.

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Question

Find the 12th term of a G.P. whose 8th term is 192 and the common ratio is 2.

Sum
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Solution

Let the first term of the geometric progression = a

Common ratio = 2

12th term =  a × 212−1 = 211 a

8th term = a × 28−1 = a × 27 = 128a

Given: 8th term = 192

∴ 128a = 192

or a = `192/128 = 3/2`

∴ 12th term = `1^11 xx 3/2`

= `2^10 xx 3`

= 1024 × 3

= 3072

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Chapter 8: Sequences and Series - EXERCISE 8.2 [Page 145]

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NCERT Mathematics [English] Class 11
Chapter 8 Sequences and Series
EXERCISE 8.2 | Q 2. | Page 145

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