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The midpoints of the sides of a square of side 1 are joined to form a new square. This procedure is repeated indefinitely. Find the sum of the perimeters of all the squares - Mathematics and Statistics

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Question

The midpoints of the sides of a square of side 1 are joined to form a new square. This procedure is repeated indefinitely. Find the sum of the perimeters of all the squares

Sum
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Solution


Perimeter of 1st square = 4

Perimeter of 2nd square = `4(1/sqrt(2))`

Perimeter of 3rd square = `4(1/2)`

and so on.

∴ Sum of the perimeters of all the squares

= `4 + 4(1/sqrt(2)) + 4(1/2) + ...`

= `4(1 + 1/sqrt(2) + (1/sqrt(2))^2 + ...)`

The terms `1,1/sqrt(2), (1/sqrt(2))^2, ...` are in G.P.

∴ a = 1, r = `1/sqrt(2)`

Since, |r| = `|1/sqrt(2)| < 1`

∴ sum to infinity exists.

∴ Sum of the perimeters of all the squares

= `4(1/(1 - 1/sqrt(2)))`

= `(4sqrt(2))/(sqrt(2) - 1)`

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Chapter 2: Sequences and Series - Exercise 2.3 [Page 34]

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