English

Find the sum to 20 terms in the geometric progression 0.15, 0.015, 0.0015,…

Advertisements
Advertisements

Question

Find the sum to 20 terms in the geometric progression 0.15, 0.015, 0.0015,…

Sum
Advertisements

Solution

The given G.P. is 0.15, 0.015, 0.00015,...

First term, a = 0.15

Common ratio, r = `0.015/0.15` = 0.1

Sum of geometric series = `("a"(1 - "r"^"n"))/(1 - "r")`

= `(0.15[1 - (0.1)^20])/(1 - (0.1))`

= `(0.15[1 - (0.1)^20])/0.9`

= `(1 - (0.1)^20)/6`

= `1/6[1 - (0.1)^20]`

shaalaa.com
  Is there an error in this question or solution?
Chapter 8: Sequences and Series - EXERCISE 8.2 [Page 145]

APPEARS IN

NCERT Mathematics [English] Class 11
Chapter 8 Sequences and Series
EXERCISE 8.2 | Q 7. | Page 145

Video TutorialsVIEW ALL [1]

RELATED QUESTIONS

Find a G.P. for which sum of the first two terms is –4 and the fifth term is 4 times the third term.


Show that the products of the corresponding terms of the sequences a, ar, ar2, …arn – 1 and A, AR, AR2, … `AR^(n-1)` form a G.P, and find the common ratio


Show that one of the following progression is a G.P. Also, find the common ratio in case:

−2/3, −6, −54, ...


Show that the sequence <an>, defined by an = \[\frac{2}{3^n}\], n ϵ N is a G.P.


Find :

the 12th term of the G.P.

\[\frac{1}{a^3 x^3}, ax, a^5 x^5 , . . .\]


Which term of the progression 18, −12, 8, ... is \[\frac{512}{729}\] ?

 

If a, b, c, d and p are different real numbers such that:
(a2 + b2 + c2) p2 − 2 (ab + bc + cd) p + (b2 + c2 + d2) ≤ 0, then show that a, b, c and d are in G.P.


Find the sum of the following geometric progression:

1, −1/2, 1/4, −1/8, ... to 9 terms;


Find the sum of the following geometric progression:

(a2 − b2), (a − b), \[\left( \frac{a - b}{a + b} \right)\] to n terms;


Find the sum of the following geometric series:

1, −a, a2, −a3, ....to n terms (a ≠ 1)


Evaluate the following:

\[\sum^{11}_{n = 1} (2 + 3^n )\]


Evaluate the following:

\[\sum^{10}_{n = 2} 4^n\]


Find the sum of the following series:

0.5 + 0.55 + 0.555 + ... to n terms.


How many terms of the sequence \[\sqrt{3}, 3, 3\sqrt{3},\]  ... must be taken to make the sum \[39 + 13\sqrt{3}\] ?


The sum of n terms of the G.P. 3, 6, 12, ... is 381. Find the value of n.


Find the sum of the following serie to infinity:

`2/5 + 3/5^2 +2/5^3 + 3/5^4 + ... ∞.`


Prove that: (21/4 . 41/8 . 81/16. 161/32 ... ∞) = 2.


If Sp denotes the sum of the series 1 + rp + r2p + ... to ∞ and sp the sum of the series 1 − rp + r2p − ... to ∞, prove that Sp + sp = 2 . S2p.


Find the rational numbers having the following decimal expansion: 

\[0 .\overline {231 }\]


Show that in an infinite G.P. with common ratio r (|r| < 1), each term bears a constant ratio to the sum of all terms that follow it.


If a, b, c, d are in G.P., prove that:

 (a + b + c + d)2 = (a + b)2 + 2 (b + c)2 + (c + d)2


If a, b, c, d are in G.P., prove that:

(b + c) (b + d) = (c + a) (c + d)


If a, b, c are in G.P., prove that the following is also in G.P.:

a3, b3, c3


If a, b, c, d are in G.P., prove that:

(a2 + b2 + c2), (ab + bc + cd), (b2 + c2 + d2) are in G.P.


If a, b, c are in G.P., then prove that:

\[\frac{a^2 + ab + b^2}{bc + ca + ab} = \frac{b + a}{c + b}\]

If pth, qth, rth and sth terms of an A.P. be in G.P., then prove that p − q, q − r, r − s are in G.P.


The value of 91/3 . 91/9 . 91/27 ... upto inf, is 


If second term of a G.P. is 2 and the sum of its infinite terms is 8, then its first term is


The two geometric means between the numbers 1 and 64 are 


Check whether the following sequence is G.P. If so, write tn.

2, 6, 18, 54, …


The number of bacteria in a culture doubles every hour. If there were 50 bacteria originally in the culture, how many bacteria will be there at the end of 5th hour?


For a G.P. If t4 = 16, t9 = 512, find S10


Find the sum to n terms of the sequence.

0.2, 0.02, 0.002, ...


Select the correct answer from the given alternative.

If for a G.P. `"t"_6/"t"_3 = 1458/54` then r = ?


Answer the following:

If for a G.P. t3 = `1/3`, t6 = `1/81` find r


Answer the following:

Find k so that k – 1, k, k + 2 are consecutive terms of a G.P.


Answer the following:

Find the sum of infinite terms of `1 + 4/5 + 7/25 + 10/125 + 13/6225 + ...`


If pth, qth, and rth terms of an A.P. and G.P. are both a, b and c respectively, show that ab–c . bc – a . ca – b = 1


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×