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Find the sum to 20 terms in the geometric progression 0.15, 0.015, 0.0015,…

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Question

Find the sum to 20 terms in the geometric progression 0.15, 0.015, 0.0015,…

Sum
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Solution

The given G.P. is 0.15, 0.015, 0.00015,...

First term, a = 0.15

Common ratio, r = `0.015/0.15` = 0.1

Sum of geometric series = `("a"(1 - "r"^"n"))/(1 - "r")`

= `(0.15[1 - (0.1)^20])/(1 - (0.1))`

= `(0.15[1 - (0.1)^20])/0.9`

= `(1 - (0.1)^20)/6`

= `1/6[1 - (0.1)^20]`

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Chapter 8: Sequences and Series - EXERCISE 8.2 [Page 145]

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NCERT Mathematics [English] Class 11
Chapter 8 Sequences and Series
EXERCISE 8.2 | Q 7. | Page 145

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