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The number of bacteria in a culture doubles every hour. If there were 50 bacteria originally in the culture, how many bacteria will be there at the end of 5th hour?

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Question

The number of bacteria in a culture doubles every hour. If there were 50 bacteria originally in the culture, how many bacteria will be there at the end of 5th hour?

Sum
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Solution

a = 50 

r = 2 

n = 5

we have, 

tn = `a*r^((n - 1))`

t5 = `(50)*(2)^(5-1)`

= 50 × (2)4

= 50 × 16

t5 = 800

 After 5th hour 800 bacterias will be there in culture.

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Chapter 2: Sequences and Series - Exercise 2.1 [Page 27]

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