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Question
The number of bacteria in a culture doubles every hour. If there were 50 bacteria originally in the culture, how many bacteria will be there at the end of 5th hour?
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Solution
a = 50
r = 2
n = 5
we have,
tn = `a*r^((n - 1))`
t5 = `(50)*(2)^(5-1)`
= 50 × (2)4
= 50 × 16
t5 = 800
After 5th hour 800 bacterias will be there in culture.
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