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Find the sum to indicated number of terms in the geometric progressions x3, x5, x7, ... n terms (if x ≠ ± 1).

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Question

Find the sum to indicated number of terms in the geometric progressions x3, x5, x7, ... n terms (if x ≠ ± 1).

Sum
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Solution

geometric progressions x3, x5, x7, …..

First term, a = x3, common ratio, r = `"x"^5/"x"^3 = "x"^2`

∴ Sum of n terms = `("a"(1 - "r"^"n"))/(1 - "r")`

= `("x"^3 xx [1 - ("x"^2)^"n"])/(1 - "x"^2)`

= `("x"^3 xx [1 - "x"^(2"n")])/(1 - "x"^2)`

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Chapter 8: Sequences and Series - EXERCISE 8.2 [Page 145]

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NCERT Mathematics [English] Class 11
Chapter 8 Sequences and Series
EXERCISE 8.2 | Q 10. | Page 145

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