मराठी

Find the sum to indicated number of terms in the geometric progressions x3, x5, x7, ... n terms (if x ≠ ± 1).

Advertisements
Advertisements

प्रश्न

Find the sum to indicated number of terms in the geometric progressions x3, x5, x7, ... n terms (if x ≠ ± 1).

बेरीज
Advertisements

उत्तर

geometric progressions x3, x5, x7, …..

First term, a = x3, common ratio, r = `"x"^5/"x"^3 = "x"^2`

∴ Sum of n terms = `("a"(1 - "r"^"n"))/(1 - "r")`

= `("x"^3 xx [1 - ("x"^2)^"n"])/(1 - "x"^2)`

= `("x"^3 xx [1 - "x"^(2"n")])/(1 - "x"^2)`

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 8: Sequences and Series - EXERCISE 8.2 [पृष्ठ १४५]

APPEARS IN

एनसीईआरटी Mathematics [English] Class 11
पाठ 8 Sequences and Series
EXERCISE 8.2 | Q 10. | पृष्ठ १४५

व्हिडिओ ट्यूटोरियलVIEW ALL [1]

संबंधित प्रश्‍न

The 5th, 8th and 11th terms of a G.P. are p, q and s, respectively. Show that q2 = ps.


The 4th term of a G.P. is square of its second term, and the first term is –3. Determine its 7thterm.


Find the sum to 20 terms in the geometric progression 0.15, 0.015, 0.0015,…


Given a G.P. with a = 729 and 7th term 64, determine S7.


Insert two numbers between 3 and 81 so that the resulting sequence is G.P.


If a and b are the roots of are roots of x2 – 3x + p = 0 , and c, d are roots of x2 – 12x + q = 0, where a, b, c, d, form a G.P. Prove that (q + p): (q – p) = 17 : 15.


Show that one of the following progression is a G.P. Also, find the common ratio in case:

4, −2, 1, −1/2, ...


Which term of the G.P. :

\[2, 2\sqrt{2}, 4, . . .\text {  is }128 ?\]


Which term of the G.P. :

\[\frac{1}{3}, \frac{1}{9}, \frac{1}{27} . . \text { . is } \frac{1}{19683} ?\]


If the G.P.'s 5, 10, 20, ... and 1280, 640, 320, ... have their nth terms equal, find the value of n.


Find three numbers in G.P. whose sum is 65 and whose product is 3375.


The product of three numbers in G.P. is 216. If 2, 8, 6 be added to them, the results are in A.P. Find the numbers.


Find the sum of the following geometric progression:

1, −1/2, 1/4, −1/8, ... to 9 terms;


Find the sum of the following geometric progression:

4, 2, 1, 1/2 ... to 10 terms.


How many terms of the sequence \[\sqrt{3}, 3, 3\sqrt{3},\]  ... must be taken to make the sum \[39 + 13\sqrt{3}\] ?


The common ratio of a G.P. is 3 and the last term is 486. If the sum of these terms be 728, find the first term.


Show that the ratio of the sum of first n terms of a G.P. to the sum of terms from (n + 1)th to (2n)th term is \[\frac{1}{r^n}\].


Let an be the nth term of the G.P. of positive numbers.

Let \[\sum^{100}_{n = 1} a_{2n} = \alpha \text { and } \sum^{100}_{n = 1} a_{2n - 1} = \beta,\] such that α ≠ β. Prove that the common ratio of the G.P. is α/β.


Prove that: (91/3 . 91/9 . 91/27 ... ∞) = 3.


Find k such that k + 9, k − 6 and 4 form three consecutive terms of a G.P.


If a, b, c are in G.P., prove that the following is also in G.P.:

a3, b3, c3


If the 4th, 10th and 16th terms of a G.P. are x, y and z respectively. Prove that x, y, z are in G.P.


If pth, qth, rth and sth terms of an A.P. be in G.P., then prove that p − q, q − r, r − s are in G.P.


If in an infinite G.P., first term is equal to 10 times the sum of all successive terms, then its common ratio is 


Given that x > 0, the sum \[\sum^\infty_{n = 1} \left( \frac{x}{x + 1} \right)^{n - 1}\] equals 


Check whether the following sequence is G.P. If so, write tn.

3, 4, 5, 6, …


For the G.P. if a = `2/3`, t6 = 162, find r.


Find five numbers in G.P. such that their product is 1024 and fifth term is square of the third term.


The numbers x − 6, 2x and x2 are in G.P. Find x


For the following G.P.s, find Sn.

`sqrt(5)`, −5, `5sqrt(5)`, −25, ...


For a G.P. if S5 = 1023 , r = 4, Find a


For a G.P. If t4 = 16, t9 = 512, find S10


Find the sum to n terms of the sequence.

0.5, 0.05, 0.005, ...


Find the sum to n terms of the sequence.

0.2, 0.02, 0.002, ...


If one invests Rs. 10,000 in a bank at a rate of interest 8% per annum, how long does it take to double the money by compound interest? [(1.08)5 = 1.47]


Select the correct answer from the given alternative.

The common ratio for the G.P. 0.12, 0.24, 0.48, is –


Answer the following:

Find `sum_("r" = 1)^"n" (2/3)^"r"`


If the pth and qth terms of a G.P. are q and p respectively, show that its (p + q)th term is `(q^p/p^q)^(1/(p - q))`


For a, b, c to be in G.P. the value of `(a - b)/(b - c)` is equal to ______.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×