मराठी

Find the sum to indicated number of terms in the geometric progressions 1, – a, a2, – a3, ... n terms (if a ≠ – 1).

Advertisements
Advertisements

प्रश्न

Find the sum to indicated number of terms in the geometric progressions 1, – a, a2, – a3, ... n terms (if a ≠ – 1).

बेरीज
Advertisements

उत्तर

Geometric progressions 1, –a, a2, –a3,  …

First term, a1 = 1, common ratio, r = `(-a)/1 = -a`

∴ Sum of n terms (Sn) = `(a_1(1 - r^n))/(1 - r)`, r > 1

= `(a(-a)^n)/(1 - r)`, r > 1

= `(1.[1 - (-a)^n])/(1 -(-a))`

= `([1 - (-a)^n])/(1 + a)`

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 8: Sequences and Series - EXERCISE 8.2 [पृष्ठ १४५]

APPEARS IN

एनसीईआरटी Mathematics [English] Class 11
पाठ 8 Sequences and Series
EXERCISE 8.2 | Q 9. | पृष्ठ १४५

व्हिडिओ ट्यूटोरियलVIEW ALL [1]

संबंधित प्रश्‍न

If a, b, c and d are in G.P. show that (a2 + b2 + c2) (b2 + c2 + d2) = (ab + bc + cd)2 .


Let S be the sum, P the product and R the sum of reciprocals of n terms in a G.P. Prove that P2Rn = Sn


Show that one of the following progression is a G.P. Also, find the common ratio in case:

−2/3, −6, −54, ...


Find :

the 10th term of the G.P.

\[\sqrt{2}, \frac{1}{\sqrt{2}}, \frac{1}{2\sqrt{2}}, . . .\]


Find three numbers in G.P. whose sum is 65 and whose product is 3375.


The sum of three numbers in G.P. is 14. If the first two terms are each increased by 1 and the third term decreased by 1, the resulting numbers are in A.P. Find the numbers.


Find the sum of the following geometric progression:

(a2 − b2), (a − b), \[\left( \frac{a - b}{a + b} \right)\] to n terms;


Find the sum of the following series:

7 + 77 + 777 + ... to n terms;


The ratio of the sum of the first three terms to that of the first 6 terms of a G.P. is 125 : 152. Find the common ratio.


Show that the ratio of the sum of first n terms of a G.P. to the sum of terms from (n + 1)th to (2n)th term is \[\frac{1}{r^n}\].


If a and b are the roots of x2 − 3x + p = 0 and c, d are the roots x2 − 12x + q = 0, where a, b, c, d form a G.P. Prove that (q + p) : (q − p) = 17 : 15.


Find the sum of 2n terms of the series whose every even term is 'a' times the term before it and every odd term is 'c' times the term before it, the first term being unity.


Express the recurring decimal 0.125125125 ... as a rational number.


Show that in an infinite G.P. with common ratio r (|r| < 1), each term bears a constant ratio to the sum of all terms that follow it.


Three numbers are in A.P. and their sum is 15. If 1, 3, 9 be added to them respectively, they form a G.P. Find the numbers.


If a, b, c are in G.P., prove that:

\[a^2 b^2 c^2 \left( \frac{1}{a^3} + \frac{1}{b^3} + \frac{1}{c^3} \right) = a^3 + b^3 + c^3\]


If a, b, c are in G.P., prove that the following is also in G.P.:

a2 + b2, ab + bc, b2 + c2


If a, b, c, d are in G.P., prove that:

(a2 − b2), (b2 − c2), (c2 − d2) are in G.P.


If \[\frac{1}{a + b}, \frac{1}{2b}, \frac{1}{b + c}\] are three consecutive terms of an A.P., prove that a, b, c are the three consecutive terms of a G.P.


If a, b, c are three distinct real numbers in G.P. and a + b + c = xb, then prove that either x< −1 or x > 3.


Given that x > 0, the sum \[\sum^\infty_{n = 1} \left( \frac{x}{x + 1} \right)^{n - 1}\] equals 


Let x be the A.M. and yz be two G.M.s between two positive numbers. Then, \[\frac{y^3 + z^3}{xyz}\]  is equal to 


The two geometric means between the numbers 1 and 64 are 


Mark the correct alternative in the following question: 

Let S be the sum, P be the product and R be the sum of the reciprocals of 3 terms of a G.P. Then p2R3 : S3 is equal to 


Check whether the following sequence is G.P. If so, write tn.

1, –5, 25, –125 …


Check whether the following sequence is G.P. If so, write tn.

3, 4, 5, 6, …


If for a sequence, tn = `(5^("n"-3))/(2^("n"-3))`, show that the sequence is a G.P. Find its first term and the common ratio


Find five numbers in G.P. such that their product is 1024 and fifth term is square of the third term.


The numbers 3, x, and x + 6 form are in G.P. Find x


For the following G.P.s, find Sn.

`sqrt(5)`, −5, `5sqrt(5)`, −25, ...


For a G.P. a = 2, r = `-2/3`, find S6


If the first term of the G.P. is 16 and its sum to infinity is `96/17` find the common ratio.


The midpoints of the sides of a square of side 1 are joined to form a new square. This procedure is repeated indefinitely. Find the sum of the perimeters of all the squares


If the A.M. of two numbers exceeds their G.M. by 2 and their H.M. by `18/5`, find the numbers.


Select the correct answer from the given alternative.

The common ratio for the G.P. 0.12, 0.24, 0.48, is –


Answer the following:

In a G.P., the fourth term is 48 and the eighth term is 768. Find the tenth term


If pth, qth, and rth terms of an A.P. and G.P. are both a, b and c respectively, show that ab–c . bc – a . ca – b = 1


For a, b, c to be in G.P. the value of `(a - b)/(b - c)` is equal to ______.


The sum of infinite number of terms of a decreasing G.P. is 4 and the sum of the terms to m squares of its terms to infinity is `16/3`, then the G.P. is ______.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×