मराठी

Find the Sum of the Following Series: 7 + 77 + 777 + ... to N Terms;

Advertisements
Advertisements

प्रश्न

Find the sum of the following series:

7 + 77 + 777 + ... to n terms;

Advertisements

उत्तर

We have,
7 + 77 + 777 + ... n terms

\[S_n\] = 7 [1 + 11 + 111 + ... n terms]

\[= \frac{7}{9}\left( 9 + 99 + 999 + . . . \text { n terms } \right)\]

\[ = \frac{7}{9}\left\{ \left( 10 - 1 \right) + \left( {10}^2 - 1 \right) + \left( {10}^3 - 1 \right) + . . . + \left( {10}^n - 1 \right) \right\}\]

\[ = \frac{7}{9}\left\{ \left( 10 + {10}^2 + {10}^3 + . . . + {10}^n \right) \right\} - \left( 1 + 1 + 1 + 1 . . . \text {n times }\right)\]

\[ = \frac{7}{9}\left\{ 10 \times \frac{\left( {10}^n - 1 \right)}{10 - 1} - n \right\} = \frac{7}{9} \left\{ \frac{10}{9}\left( {10}^n - 1 \right) - n \right\}\]

\[ = \frac{7}{81}\left\{ {10}^{n + 1} - 9n - 10 \right\}\]

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?

व्हिडिओ ट्यूटोरियलVIEW ALL [1]

संबंधित प्रश्‍न

Evaluate `sum_(k=1)^11 (2+3^k )`


If the 4th, 10th and 16th terms of a G.P. are x, y and z, respectively. Prove that x, y, z are in G.P.


Find the sum to n terms of the sequence, 8, 88, 888, 8888… .


If a, b, c and d are in G.P. show that (a2 + b2 + c2) (b2 + c2 + d2) = (ab + bc + cd)2 .


Show that the sequence <an>, defined by an = \[\frac{2}{3^n}\], n ϵ N is a G.P.


Find : 

nth term of the G.P.

\[\sqrt{3}, \frac{1}{\sqrt{3}}, \frac{1}{3\sqrt{3}}, . . .\]


If the G.P.'s 5, 10, 20, ... and 1280, 640, 320, ... have their nth terms equal, find the value of n.


If a, b, c, d and p are different real numbers such that:
(a2 + b2 + c2) p2 − 2 (ab + bc + cd) p + (b2 + c2 + d2) ≤ 0, then show that a, b, c and d are in G.P.


Find the sum of the following series:

0.5 + 0.55 + 0.555 + ... to n terms.


Find the sum of the following series:

0.6 + 0.66 + 0.666 + .... to n terms


The common ratio of a G.P. is 3 and the last term is 486. If the sum of these terms be 728, find the first term.


If S1, S2, ..., Sn are the sums of n terms of n G.P.'s whose first term is 1 in each and common ratios are 1, 2, 3, ..., n respectively, then prove that S1 + S2 + 2S3 + 3S4 + ... (n − 1) Sn = 1n + 2n + 3n + ... + nn.


A G.P. consists of an even number of terms. If the sum of all the terms is 5 times the sum of the terms occupying the odd places. Find the common ratio of the G.P.


Find the sum of 2n terms of the series whose every even term is 'a' times the term before it and every odd term is 'c' times the term before it, the first term being unity.


Find the sum of the following serie to infinity:

8 +  \[4\sqrt{2}\] + 4 + ... ∞


Find the sum of the following series to infinity:

10 − 9 + 8.1 − 7.29 + ... ∞


Prove that: (91/3 . 91/9 . 91/27 ... ∞) = 3.


If a, b, c are three distinct real numbers in G.P. and a + b + c = xb, then prove that either x< −1 or x > 3.


Insert 5 geometric means between 16 and \[\frac{1}{4}\] .


If logxa, ax/2 and logb x are in G.P., then write the value of x.


Let x be the A.M. and yz be two G.M.s between two positive numbers. Then, \[\frac{y^3 + z^3}{xyz}\]  is equal to 


For what values of x, the terms `4/3`, x, `4/27` are in G.P.?


The number of bacteria in a culture doubles every hour. If there were 50 bacteria originally in the culture, how many bacteria will be there at the end of 5th hour?


The numbers x − 6, 2x and x2 are in G.P. Find 1st term


For a sequence, if Sn = 2(3n –1), find the nth term, hence show that the sequence is a G.P.


If Sn, S2n, S3n are the sum of n, 2n, 3n terms of a G.P. respectively, then verify that Sn (S3n – S2n) = (S2n – Sn)2.


Find: `sum_("r" = 1)^10 5 xx 3^"r"`


If the common ratio of a G.P. is `2/3` and sum to infinity is 12. Find the first term


The sum of an infinite G.P. is 5 and the sum of the squares of these terms is 15 find the G.P.


The midpoints of the sides of a square of side 1 are joined to form a new square. This procedure is repeated indefinitely. Find the sum of the areas of all the squares


Select the correct answer from the given alternative.

If common ratio of the G.P is 5, 5th term is 1875, the first term is -


Select the correct answer from the given alternative.

Sum to infinity of a G.P. 5, `-5/2, 5/4, -5/8, 5/16,...` is –


Answer the following:

For a G.P. if t2 = 7, t4 = 1575 find a


If pth, qth, and rth terms of an A.P. and G.P. are both a, b and c respectively, show that ab–c . bc – a . ca – b = 1


The sum of the infinite series `1 + 5/6 + 12/6^2 + 22/6^3 + 35/6^4 + 51/6^5 + 70/6^6 + ....` is equal to ______.


If `e^((cos^2x + cos^4x + cos^6x + ...∞)log_e2` satisfies the equation t2 – 9t + 8 = 0, then the value of `(2sinx)/(sinx + sqrt(3)cosx)(0 < x ,< π/2)` is ______.


The sum of the first three terms of a G.P. is S and their product is 27. Then all such S lie in ______.


For an increasing G.P. a1, a2 , a3 ........., an, if a6 = 4a4, a9 – a7 = 192, then the value of `sum_(i = 1)^∞ 1/a_i` is ______.


If in a geometric progression {an}, a1 = 3, an = 96 and Sn = 189, then the value of n is ______.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×