मराठी

Prove That: (91/3 . 91/9 . 91/27 ... ∞) = 3.

Advertisements
Advertisements

प्रश्न

Prove that: (91/3 . 91/9 . 91/27 ... ∞) = 3.

Advertisements

उत्तर

\[\text { LHS  }= 9^\frac{1}{3} . 9^\frac{1}{9} . 9^\frac{1}{27} . . . \infty \]

\[ = 9^\left( \frac{1}{3} + \frac{1}{9}\frac{1}{27} . \right) \]

\[ = 9^\left\{ \frac{\left( \frac{1}{3} \right)}{\left( 1 - \frac{1}{3} \right)} \right\} \]

\[ = 9^\frac{\left( \frac{1}{3} \right)}{\left( 1 - \frac{1}{3} \right)} \]

\[ = \sqrt{9}\]

\[ = 3 =\text {  RHS }\]

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 20: Geometric Progression - Exercise 20.4 [पृष्ठ ३९]

APPEARS IN

आर.डी. शर्मा Mathematics [English] Class 11
पाठ 20 Geometric Progression
Exercise 20.4 | Q 2 | पृष्ठ ३९

व्हिडिओ ट्यूटोरियलVIEW ALL [1]

संबंधित प्रश्‍न

Find the sum to 20 terms in the geometric progression 0.15, 0.015, 0.0015,…


Find the sum to indicated number of terms in the geometric progressions 1, – a, a2, – a3, ... n terms (if a ≠ – 1).


Find the sum to indicated number of terms in the geometric progressions x3, x5, x7, ... n terms (if x ≠ ± 1).


Evaluate `sum_(k=1)^11 (2+3^k )`


The sum of first three terms of a G.P. is 16 and the sum of the next three terms is 128. Determine the first term, the common ratio and the sum to n terms of the G.P.


Find the sum of the products of the corresponding terms of the sequences `2, 4, 8, 16, 32 and 128, 32, 8, 2, 1/2`


Show that the products of the corresponding terms of the sequences a, ar, ar2, …arn – 1 and A, AR, AR2, … `AR^(n-1)` form a G.P, and find the common ratio


if `(a+ bx)/(a - bx) = (b +cx)/(b - cx) = (c + dx)/(c- dx) (x != 0)` then show that a, b, c and d are in G.P.


Find :

the 12th term of the G.P.

\[\frac{1}{a^3 x^3}, ax, a^5 x^5 , . . .\]


The ratio of the sum of the first three terms to that of the first 6 terms of a G.P. is 125 : 152. Find the common ratio.


The 4th and 7th terms of a G.P. are \[\frac{1}{27} \text { and } \frac{1}{729}\] respectively. Find the sum of n terms of the G.P.


How many terms of the G.P. `3, 3/2, 3/4` ..... are needed to give the sum `3069/512`?


One side of an equilateral triangle is 18 cm. The mid-points of its sides are joined to form another triangle whose mid-points, in turn, are joined to form still another triangle. The process is continued indefinitely. Find the sum of the (i) perimeters of all the triangles. (ii) areas of all triangles.


If a, b, c are in G.P., prove that \[\frac{1}{\log_a m}, \frac{1}{\log_b m}, \frac{1}{\log_c m}\] are in A.P.


Three numbers are in A.P. and their sum is 15. If 1, 3, 9 be added to them respectively, they form a G.P. Find the numbers.


If a, b, c are in G.P., prove that:

\[\frac{(a + b + c )^2}{a^2 + b^2 + c^2} = \frac{a + b + c}{a - b + c}\]


If a, b, c are in G.P., prove that the following is also in G.P.:

a3, b3, c3


If a, b, c are in A.P., b,c,d are in G.P. and \[\frac{1}{c}, \frac{1}{d}, \frac{1}{e}\] are in A.P., prove that a, c,e are in G.P.


Insert 6 geometric means between 27 and  \[\frac{1}{81}\] .


Insert 5 geometric means between 16 and \[\frac{1}{4}\] .


The sum of two numbers is 6 times their geometric means, show that the numbers are in the ratio `(3+2sqrt2):(3-2sqrt2)`.


If pth, qth and rth terms of an A.P. are in G.P., then the common ratio of this G.P. is


If x = (43) (46) (46) (49) .... (43x) = (0.0625)−54, the value of x is 


Given that x > 0, the sum \[\sum^\infty_{n = 1} \left( \frac{x}{x + 1} \right)^{n - 1}\] equals 


Check whether the following sequence is G.P. If so, write tn.

2, 6, 18, 54, …


If p, q, r, s are in G.P. show that p + q, q + r, r + s are also in G.P.


For the following G.P.s, find Sn

0.7, 0.07, 0.007, .....


For the following G.P.s, find Sn.

`sqrt(5)`, −5, `5sqrt(5)`, −25, ...


Find: `sum_("r" = 1)^10 5 xx 3^"r"`


Determine whether the sum to infinity of the following G.P.s exist, if exists find them:

`-3, 1, (-1)/3, 1/9, ...`


Express the following recurring decimal as a rational number:

`2.3bar(5)`


The midpoints of the sides of a square of side 1 are joined to form a new square. This procedure is repeated indefinitely. Find the sum of the areas of all the squares


The sum of 3 terms of a G.P. is `21/4` and their product is 1 then the common ratio is ______.


Answer the following:

Find five numbers in G.P. such that their product is 243 and sum of second and fourth number is 10.


Answer the following:

Find the nth term of the sequence 0.6, 0.66, 0.666, 0.6666, ...


In a G.P. of even number of terms, the sum of all terms is 5 times the sum of the odd terms. The common ratio of the G.P. is ______.


The sum of the first three terms of a G.P. is S and their product is 27. Then all such S lie in ______.


Let A1, A2, A3, .... be an increasing geometric progression of positive real numbers. If A1A3A5A7 = `1/1296` and A2 + A4 = `7/36`, then the value of A6 + A8 + A10 is equal to ______. 


If the expansion in powers of x of the function `1/((1 - ax)(1 - bx))` is a0 + a1x + a2x2 + a3x3 ....... then an is ______.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×