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Prove That: (91/3 . 91/9 . 91/27 ... ∞) = 3.

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Question

Prove that: (91/3 . 91/9 . 91/27 ... ∞) = 3.

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Solution

\[\text { LHS  }= 9^\frac{1}{3} . 9^\frac{1}{9} . 9^\frac{1}{27} . . . \infty \]

\[ = 9^\left( \frac{1}{3} + \frac{1}{9}\frac{1}{27} . \right) \]

\[ = 9^\left\{ \frac{\left( \frac{1}{3} \right)}{\left( 1 - \frac{1}{3} \right)} \right\} \]

\[ = 9^\frac{\left( \frac{1}{3} \right)}{\left( 1 - \frac{1}{3} \right)} \]

\[ = \sqrt{9}\]

\[ = 3 =\text {  RHS }\]

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Chapter 20: Geometric Progression - Exercise 20.4 [Page 39]

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R.D. Sharma Mathematics [English] Class 11
Chapter 20 Geometric Progression
Exercise 20.4 | Q 2 | Page 39

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