English

Find the sum of the following geometric series: √7,√21,3⁢√7,... to n terms

Advertisements
Advertisements

Question

Find the sum of the following geometric series:

`sqrt7, sqrt21, 3sqrt7,...` to n terms

Sum
Advertisements

Solution

The given geometric series is:

`sqrt7, sqrt21, 3sqrt7,...` to n terms

Step 1: Identify the first term (a)

a = `sqrt7`

Step 2: Find the common ratio (r)

`r = (sqrt21)/(sqrt7) = sqrt3`

Check with next term:

`(3sqrt7)/(sqrt21) = sqrt3`

So the ratio is correct.

Step 3: Use the sum of n terms formula

For a geometric series:

`S_n = a(r^n - 1)/(r - 1)`

Substitute a = √7 and r = √3:

`S_n = sqrt7((sqrt3)^n - 1)/(sqrt3 - 1)`

shaalaa.com
  Is there an error in this question or solution?
Chapter 20: Geometric Progression - Exercise 20.3 [Page 27]

APPEARS IN

R.D. Sharma Mathematics [English] Class 11
Chapter 20 Geometric Progression
Exercise 20.3 | Q 2.9 | Page 27

Video TutorialsVIEW ALL [1]

RELATED QUESTIONS

If a, b, c and d are in G.P. show that (a2 + b2 + c2) (b2 + c2 + d2) = (ab + bc + cd)2 .


If f is a function satisfying f (x +y) = f(x) f(y) for all x, y ∈ N such that f(1) = 3 and `sum_(x = 1)^n` f(x) = 120, find the value of n.


The sum of some terms of G.P. is 315 whose first term and the common ratio are 5 and 2, respectively. Find the last term and the number of terms.


Show that one of the following progression is a G.P. Also, find the common ratio in case:

−2/3, −6, −54, ...


The sum of first three terms of a G.P. is 13/12 and their product is − 1. Find the G.P.


The sum of three numbers in G.P. is 14. If the first two terms are each increased by 1 and the third term decreased by 1, the resulting numbers are in A.P. Find the numbers.


Find three numbers in G.P. whose product is 729 and the sum of their products in pairs is 819.


Find the sum of the following geometric progression:

(a2 − b2), (a − b), \[\left( \frac{a - b}{a + b} \right)\] to n terms;


Find the sum of the following geometric series:

\[\frac{2}{9} - \frac{1}{3} + \frac{1}{2} - \frac{3}{4} + . . . \text { to 5 terms };\]


How many terms of the G.P. 3, 3/2, 3/4, ... be taken together to make \[\frac{3069}{512}\] ?


If S1, S2, S3 be respectively the sums of n, 2n, 3n terms of a G.P., then prove that \[S_1^2 + S_2^2\] = S1 (S2 + S3).


Find the rational numbers having the following decimal expansion: 

\[0 . 6\overline8\]


If a, b, c are in G.P., prove that:

\[a^2 b^2 c^2 \left( \frac{1}{a^3} + \frac{1}{b^3} + \frac{1}{c^3} \right) = a^3 + b^3 + c^3\]


If a, b, c are in G.P., prove that the following is also in G.P.:

a3, b3, c3


If (a − b), (b − c), (c − a) are in G.P., then prove that (a + b + c)2 = 3 (ab + bc + ca)


If xa = xb/2 zb/2 = zc, then prove that \[\frac{1}{a}, \frac{1}{b}, \frac{1}{c}\] are in A.P.

  

If A be one A.M. and pq be two G.M.'s between two numbers, then 2 A is equal to 


If x is positive, the sum to infinity of the series \[\frac{1}{1 + x} - \frac{1 - x}{(1 + x )^2} + \frac{(1 - x )^2}{(1 + x )^3} - \frac{(1 - x )^3}{(1 + x )^4} + . . . . . . is\]


If x = (43) (46) (46) (49) .... (43x) = (0.0625)−54, the value of x is 


Let x be the A.M. and yz be two G.M.s between two positive numbers. Then, \[\frac{y^3 + z^3}{xyz}\]  is equal to 


Check whether the following sequence is G.P. If so, write tn.

2, 6, 18, 54, …


Find three numbers in G.P. such that their sum is 21 and sum of their squares is 189.


The fifth term of a G.P. is x, eighth term of a G.P. is y and eleventh term of a G.P. is z verify whether y2 = xz


The numbers 3, x, and x + 6 form are in G.P. Find x


The numbers 3, x, and x + 6 form are in G.P. Find nth term


The numbers x − 6, 2x and x2 are in G.P. Find 1st term


If Sn, S2n, S3n are the sum of n, 2n, 3n terms of a G.P. respectively, then verify that Sn (S3n – S2n) = (S2n – Sn)2.


Find : `sum_("n" = 1)^oo 0.4^"n"`


If the A.M. of two numbers exceeds their G.M. by 2 and their H.M. by `18/5`, find the numbers.


Select the correct answer from the given alternative.

The common ratio for the G.P. 0.12, 0.24, 0.48, is –


Select the correct answer from the given alternative.

The tenth term of the geometric sequence `1/4, (-1)/2, 1, -2,` ... is –


Answer the following:

In a G.P., the fourth term is 48 and the eighth term is 768. Find the tenth term


Answer the following:

For a sequence Sn = 4(7n – 1) verify that the sequence is a G.P.


Answer the following:

Find `sum_("r" = 1)^"n" (2/3)^"r"`


If pth, qth, and rth terms of an A.P. and G.P. are both a, b and c respectively, show that ab–c . bc – a . ca – b = 1


If x, 2y, 3z are in A.P., where the distinct numbers x, y, z are in G.P. then the common ratio of the G.P. is ______.


The sum or difference of two G.P.s, is again a G.P.


Find a G.P. for which sum of the first two terms is – 4 and the fifth term is 4 times the third term.


Let A1, A2, A3, .... be an increasing geometric progression of positive real numbers. If A1A3A5A7 = `1/1296` and A2 + A4 = `7/36`, then the value of A6 + A8 + A10 is equal to ______. 


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×