English

The numbers 3, x, and x + 6 form are in G.P. Find nth term

Advertisements
Advertisements

Question

The numbers 3, x, and x + 6 form are in G.P. Find nth term

Sum
Advertisements

Solution

When x = 6, nth term is given by

tn = arn–1, where a = 3, r = `"x"/3 = 6/3` = 2

∴ tn = 3(2)n–1

When x = – 3, nth term is given by

tn = arn–1, where a = 3, r = `"x"/3 = (-3)/3` = – 1

∴ tn = 3(– 1)n–1

Hence, nth term = 3(2)n–1 or 3(– 1)n–1.

shaalaa.com
  Is there an error in this question or solution?
Chapter 2: Sequences and Series - Exercise 2.1 [Page 28]

APPEARS IN

RELATED QUESTIONS

For what values of x, the numbers  `-2/7, x, -7/2` are in G.P?


Find the sum to indicated number of terms in the geometric progressions 1, – a, a2, – a3, ... n terms (if a ≠ – 1).


Find the sum to n terms of the sequence, 8, 88, 888, 8888… .


If the pth, qth and rth terms of a G.P. are a, b and c, respectively. Prove that `a^(q - r) b^(r-p) c^(p-q) = 1`.


If the first and the nth term of a G.P. are a ad b, respectively, and if P is the product of n terms, prove that P2 = (ab)n.


Show that one of the following progression is a G.P. Also, find the common ratio in case:

\[a, \frac{3 a^2}{4}, \frac{9 a^3}{16}, . . .\]


Show that the sequence <an>, defined by an = \[\frac{2}{3^n}\], n ϵ N is a G.P.


Find:
the ninth term of the G.P. 1, 4, 16, 64, ...


Which term of the progression 18, −12, 8, ... is \[\frac{512}{729}\] ?

 

Find three numbers in G.P. whose sum is 38 and their product is 1728.


Find three numbers in G.P. whose product is 729 and the sum of their products in pairs is 819.


Find the sum of the following series:

7 + 77 + 777 + ... to n terms;


The common ratio of a G.P. is 3 and the last term is 486. If the sum of these terms be 728, find the first term.


The ratio of the sum of the first three terms to that of the first 6 terms of a G.P. is 125 : 152. Find the common ratio.


Find the sum :

\[\sum^{10}_{n = 1} \left[ \left( \frac{1}{2} \right)^{n - 1} + \left( \frac{1}{5} \right)^{n + 1} \right] .\]


If S1, S2, S3 be respectively the sums of n, 2n, 3n terms of a G.P., then prove that \[S_1^2 + S_2^2\] = S1 (S2 + S3).


A G.P. consists of an even number of terms. If the sum of all the terms is 5 times the sum of the terms occupying the odd places. Find the common ratio of the G.P.


Prove that: (21/4 . 41/8 . 81/16. 161/32 ... ∞) = 2.


Find the rational numbers having the following decimal expansion: 

\[0 . \overline3\]


If S denotes the sum of an infinite G.P. S1 denotes the sum of the squares of its terms, then prove that the first term and common ratio are respectively

\[\frac{2S S_1}{S^2 + S_1}\text {  and } \frac{S^2 - S_1}{S^2 + S_1}\]


If a, b, c are in G.P., prove that log a, log b, log c are in A.P.


The sum of three numbers in G.P. is 56. If we subtract 1, 7, 21 from these numbers in that order, we obtain an A.P. Find the numbers.


If a, b, c are in G.P., prove that:

\[a^2 b^2 c^2 \left( \frac{1}{a^3} + \frac{1}{b^3} + \frac{1}{c^3} \right) = a^3 + b^3 + c^3\]


If a, b, c are in G.P., prove that:

\[\frac{1}{a^2 - b^2} + \frac{1}{b^2} = \frac{1}{b^2 - c^2}\]


If a, b, c, d are in G.P., prove that:

(b + c) (b + d) = (c + a) (c + d)


If a, b, c are in A.P. and a, b, d are in G.P., then prove that a, a − b, d − c are in G.P.


If \[\frac{1}{a + b}, \frac{1}{2b}, \frac{1}{b + c}\] are three consecutive terms of an A.P., prove that a, b, c are the three consecutive terms of a G.P.


Find the geometric means of the following pairs of number:

−8 and −2


If the fifth term of a G.P. is 2, then write the product of its 9 terms.


If a = 1 + b + b2 + b3 + ... to ∞, then write b in terms of a.


If the first term of a G.P. a1a2a3, ... is unity such that 4 a2 + 5 a3 is least, then the common ratio of G.P. is


The numbers x − 6, 2x and x2 are in G.P. Find 1st term


For a G.P. a = 2, r = `-2/3`, find S6


For a G.P. if S5 = 1023 , r = 4, Find a


Find the sum to n terms of the sequence.

0.2, 0.02, 0.002, ...


Express the following recurring decimal as a rational number:

`2.3bar(5)`


The sum of 3 terms of a G.P. is `21/4` and their product is 1 then the common ratio is ______.


Answer the following:

For a sequence , if tn = `(5^("n" - 2))/(7^("n" - 3))`, verify whether the sequence is a G.P. If it is a G.P., find its first term and the common ratio.


Answer the following:

Find the sum of infinite terms of `1 + 4/5 + 7/25 + 10/125 + 13/6225 + ...`


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×