हिंदी

Find the sum of the following geometric series: √7,√21,3⁢√7,... to n terms

Advertisements
Advertisements

प्रश्न

Find the sum of the following geometric series:

`sqrt7, sqrt21, 3sqrt7,...` to n terms

योग
Advertisements

उत्तर

The given geometric series is:

`sqrt7, sqrt21, 3sqrt7,...` to n terms

Step 1: Identify the first term (a)

a = `sqrt7`

Step 2: Find the common ratio (r)

`r = (sqrt21)/(sqrt7) = sqrt3`

Check with next term:

`(3sqrt7)/(sqrt21) = sqrt3`

So the ratio is correct.

Step 3: Use the sum of n terms formula

For a geometric series:

`S_n = a(r^n - 1)/(r - 1)`

Substitute a = √7 and r = √3:

`S_n = sqrt7((sqrt3)^n - 1)/(sqrt3 - 1)`

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 20: Geometric Progression - Exercise 20.3 [पृष्ठ २७]

APPEARS IN

आर.डी. शर्मा Mathematics [English] Class 11
अध्याय 20 Geometric Progression
Exercise 20.3 | Q 2.9 | पृष्ठ २७

वीडियो ट्यूटोरियलVIEW ALL [1]

संबंधित प्रश्न

Find the sum to indicated number of terms of the geometric progressions `sqrt7, sqrt21,3sqrt7`...n terms.


Show that the products of the corresponding terms of the sequences a, ar, ar2, …arn – 1 and A, AR, AR2, … `AR^(n-1)` form a G.P, and find the common ratio


Insert two numbers between 3 and 81 so that the resulting sequence is G.P.


If a and b are the roots of are roots of x2 – 3x + p = 0 , and c, d are roots of x2 – 12x + q = 0, where a, b, c, d, form a G.P. Prove that (q + p): (q – p) = 17 : 15.


Find:
the ninth term of the G.P. 1, 4, 16, 64, ...


Which term of the G.P. :

\[\sqrt{2}, \frac{1}{\sqrt{2}}, \frac{1}{2\sqrt{2}}, \frac{1}{4\sqrt{2}}, . . . \text { is }\frac{1}{512\sqrt{2}}?\]


Which term of the G.P.: `sqrt3, 3, 3sqrt3`, ... is 729?


The seventh term of a G.P. is 8 times the fourth term and 5th term is 48. Find the G.P.


If the G.P.'s 5, 10, 20, ... and 1280, 640, 320, ... have their nth terms equal, find the value of n.


If \[\frac{a + bx}{a - bx} = \frac{b + cx}{b - cx} = \frac{c + dx}{c - dx}\] (x ≠ 0), then show that abc and d are in G.P.


Find the sum of the following geometric series:

(x +y) + (x2 + xy + y2) + (x3 + x2y + xy2 + y3) + ... to n terms;


The ratio of the sum of the first three terms to that of the first 6 terms of a G.P. is 125 : 152. Find the common ratio.


Find the sum of 2n terms of the series whose every even term is 'a' times the term before it and every odd term is 'c' times the term before it, the first term being unity.


If S denotes the sum of an infinite G.P. S1 denotes the sum of the squares of its terms, then prove that the first term and common ratio are respectively

\[\frac{2S S_1}{S^2 + S_1}\text {  and } \frac{S^2 - S_1}{S^2 + S_1}\]


Three numbers are in A.P. and their sum is 15. If 1, 3, 9 be added to them respectively, they form a G.P. Find the numbers.


The sum of three numbers a, b, c in A.P. is 18. If a and b are each increased by 4 and c is increased by 36, the new numbers form a G.P. Find a, b, c.


If a, b, c are in A.P. and a, b, d are in G.P., then prove that a, a − b, d − c are in G.P.


If pth, qth, rth and sth terms of an A.P. be in G.P., then prove that p − q, q − r, r − s are in G.P.


If a, b, c are in A.P. and a, x, b and b, y, c are in G.P., show that x2, b2, y2 are in A.P.


If the fifth term of a G.P. is 2, then write the product of its 9 terms.


If S be the sum, P the product and R be the sum of the reciprocals of n terms of a GP, then P2 is equal to


The product (32), (32)1/6 (32)1/36 ... to ∞ is equal to 


The two geometric means between the numbers 1 and 64 are 


Check whether the following sequence is G.P. If so, write tn.

3, 4, 5, 6, …


Which term of the G.P. 5, 25, 125, 625, … is 510?


Find three numbers in G.P. such that their sum is 21 and sum of their squares is 189.


Find five numbers in G.P. such that their product is 1024 and fifth term is square of the third term.


Mosquitoes are growing at a rate of 10% a year. If there were 200 mosquitoes in the beginning. Write down the number of mosquitoes after n years.


The numbers x − 6, 2x and x2 are in G.P. Find 1st term


For a G.P. If t3 = 20 , t6 = 160 , find S7


Find the sum to n terms of the sequence.

0.5, 0.05, 0.005, ...


If S, P, R are the sum, product, and sum of the reciprocals of n terms of a G.P. respectively, then verify that `["S"/"R"]^"n"` = P


If the first term of the G.P. is 16 and its sum to infinity is `96/17` find the common ratio.


Find : `sum_("r" = 1)^oo (-1/3)^"r"`


The midpoints of the sides of a square of side 1 are joined to form a new square. This procedure is repeated indefinitely. Find the sum of the perimeters of all the squares


Select the correct answer from the given alternative.

The tenth term of the geometric sequence `1/4, (-1)/2, 1, -2,` ... is –


The sum of 3 terms of a G.P. is `21/4` and their product is 1 then the common ratio is ______.


If a, b, c, d are in G.P., prove that a2 – b2, b2 – c2, c2 – d2 are also in G.P.


If in a geometric progression {an}, a1 = 3, an = 96 and Sn = 189, then the value of n is ______.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×