हिंदी

Answer the following: In a G.P., the fourth term is 48 and the eighth term is 768. Find the tenth term

Advertisements
Advertisements

प्रश्न

Answer the following:

In a G.P., the fourth term is 48 and the eighth term is 768. Find the tenth term

योग
Advertisements

उत्तर

Given, t4 = 48, t8 = 768

tn = arn–1

∴ t4 = ar3

∴ ar3 = 48    ...(i)

and ar7 = 768   ...(ii)

Equation (ii) ÷ equation (i), we get

∴ `"ar"^7/"ar"^3 = 768/48`

∴ r4 = 16

∴ r = 2

Substituting r = 2 (i), we get

a.(23) = 48

∴ a = 6

∴ t10 = ar9

∴ t10 = ar9

= 6(29)

= 3072

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 2: Sequences and Series - Miscellaneous Exercise 2.2 [पृष्ठ ४१]

APPEARS IN

बालभारती Mathematics and Statistics 2 (Arts and Science) [English] Standard 11 Maharashtra State Board
अध्याय 2 Sequences and Series
Miscellaneous Exercise 2.2 | Q II. (1) | पृष्ठ ४१

संबंधित प्रश्न

Find the 12th term of a G.P. whose 8th term is 192 and the common ratio is 2.


Find the sum to indicated number of terms in the geometric progressions x3, x5, x7, ... n terms (if x ≠ ± 1).


Find a G.P. for which sum of the first two terms is –4 and the fifth term is 4 times the third term.


Find four numbers forming a geometric progression in which third term is greater than the first term by 9, and the second term is greater than the 4th by 18.


Insert two numbers between 3 and 81 so that the resulting sequence is G.P.


Find :

the 8th term of the G.P. 0.3, 0.06, 0.012, ...


Find :

the 12th term of the G.P.

\[\frac{1}{a^3 x^3}, ax, a^5 x^5 , . . .\]


Which term of the G.P. :

\[\frac{1}{3}, \frac{1}{9}, \frac{1}{27} . . \text { . is } \frac{1}{19683} ?\]


In a GP the 3rd term is 24 and the 6th term is 192. Find the 10th term.


The product of three numbers in G.P. is 216. If 2, 8, 6 be added to them, the results are in A.P. Find the numbers.


Find the sum of the following geometric progression:

1, −1/2, 1/4, −1/8, ... to 9 terms;


Find the sum of the following geometric progression:

4, 2, 1, 1/2 ... to 10 terms.


Find the sum of the following series:

7 + 77 + 777 + ... to n terms;


Find the sum of the following series:

0.6 + 0.66 + 0.666 + .... to n terms


How many terms of the G.P. 3, 3/2, 3/4, ... be taken together to make \[\frac{3069}{512}\] ?


Find the rational numbers having the following decimal expansion: 

\[3 . 5\overline 2\]


One side of an equilateral triangle is 18 cm. The mid-points of its sides are joined to form another triangle whose mid-points, in turn, are joined to form still another triangle. The process is continued indefinitely. Find the sum of the (i) perimeters of all the triangles. (ii) areas of all triangles.


The sum of first two terms of an infinite G.P. is 5 and each term is three times the sum of the succeeding terms. Find the G.P.


The sum of three numbers which are consecutive terms of an A.P. is 21. If the second number is reduced by 1 and the third is increased by 1, we obtain three consecutive terms of a G.P. Find the numbers.


If a, b, c are in G.P., prove that:

\[\frac{1}{a^2 - b^2} + \frac{1}{b^2} = \frac{1}{b^2 - c^2}\]


If the 4th, 10th and 16th terms of a G.P. are x, y and z respectively. Prove that x, y, z are in G.P.


If a, b, c are in A.P. and a, b, d are in G.P., show that a, (a − b), (d − c) are in G.P.


Insert 6 geometric means between 27 and  \[\frac{1}{81}\] .


Find the geometric means of the following pairs of number:

−8 and −2


In a G.P. of even number of terms, the sum of all terms is five times the sum of the odd terms. The common ratio of the G.P. is 


For the G.P. if r = `1/3`, a = 9 find t7


The numbers 3, x, and x + 6 form are in G.P. Find x


The numbers x − 6, 2x and x2 are in G.P. Find nth term


For the following G.P.s, find Sn

0.7, 0.07, 0.007, .....


For a G.P. If t3 = 20 , t6 = 160 , find S7


Find: `sum_("r" = 1)^10(3 xx 2^"r")`


The value of a house appreciates 5% per year. How much is the house worth after 6 years if its current worth is ₹ 15 Lac. [Given: (1.05)5 = 1.28, (1.05)6 = 1.34]


Find `sum_("r" = 0)^oo (-8)(-1/2)^"r"` 


Answer the following:

For a G.P. a = `4/3` and t7 = `243/1024`, find the value of r


At the end of each year the value of a certain machine has depreciated by 20% of its value at the beginning of that year. If its initial value was Rs 1250, find the value at the end of 5 years.


Let S be the sum, P be the product and R be the sum of the reciprocals of 3 terms of a G.P. Then P2 R3 : S3 is equal to ______.


Let A1, A2, A3, .... be an increasing geometric progression of positive real numbers. If A1A3A5A7 = `1/1296` and A2 + A4 = `7/36`, then the value of A6 + A8 + A10 is equal to ______. 


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×