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If 5th, 8th and 11th Terms of a G.P. Are P. Q and S Respectively, Prove that Q2 = Ps. - Mathematics

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प्रश्न

If 5th, 8th and 11th terms of a G.P. are p. q and s respectively, prove that q2 = ps.

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उत्तर

\[\text { Let a be the first term and r be the common ratio of the given G . P } . \]

\[ \therefore p = 5^{th}\text {  term } \]

\[ \Rightarrow p = a r^4 . . . \left( 1 \right)\]

\[q = 8^{th} \text { term } \]

\[ \Rightarrow q = a r^7 . . . \left( 2 \right)\]

\[s = {11}^{th} \]

\[ \Rightarrow s = a r^{10} . . . \left( 3 \right)\]

\[\text { Now, } q^2 = \left( a r^7 \right)^2 = a^2 r^{14} \]

\[ \Rightarrow \left( a r^4 \right) \left( a r^{10} \right) = ps \left[ \text { From } \left( 1 \right) \text { and } \left( 3 \right) \right]\]

\[ \therefore q^2 = ps\]

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अध्याय 20: Geometric Progression - Exercise 20.1 [पृष्ठ १०]

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आरडी शर्मा Mathematics [English] Class 11
अध्याय 20 Geometric Progression
Exercise 20.1 | Q 12 | पृष्ठ १०

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